In: Math
The fill amount of bottles of a soft drink is normally distributed, with a mean of 2.0 liters and a standard deviation of 0.05 liter. If you select a random sample of 25 bottles, what is the probability that the sample mean will be:
A.) Between 1.99 and 2.0 liters
B.) Below 1.98 liters
C.) Greater than 2.01 liters
D.) The probability is 99% that the sample mean amount of soft drink will be at least how much?
E.) The probability is 99% that the sample mean amount of soft drink will be between which two amounts?
Part a)
P ( 1.99 < X < 2 )
Standardizing the value
Z = -1
Z = 0
P ( -1 < Z < 0 )
P ( 1.99 < X < 2 ) = P ( Z < 0 ) - P ( Z < -1 )
P ( 1.99 < X < 2 ) = 0.5 - 0.1587
P ( 1.99 < X < 2 ) = 0.3413
Part b)
P ( X < 1.98 )
Standardizing the value
Z = -2
P ( X < 1.98 ) = P ( Z < -2 )
P ( X < 1.98 ) = 0.0228
Part c)
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P ( X > 2.01 ) = 1 - P ( X < 2.01 ) | |||||||||
Standardizing the value | |||||||||
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Z = 1 | |||||||||
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P ( Z > 1 ) | |||||||||
P ( X > 2.01 ) = 1 - P ( Z < 1 ) | |||||||||
P ( X > 2.01 ) = 1 - 0.8413 | |||||||||
P ( X > 2.01 ) = 0.1587 |
Part d)
P ( Z > ? ) = 99% = 0.99
P ( Z > ? ) = 1 - P ( Z < ? ) = 1 - 0.99 = 0.01
Looking for the probability 0.01 in standard normal table to find the critical value z = -2.33
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Part e) P ( a < Z < b ) = 99% = 0.99 Area above the mean = 0.5 + ( 0.99 / 2 ) = 0.5 + 0.495 = 0.995 Looking for the probability 0.995 in standard normal table to find the critical value Z = 2.58
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