Question

The language is C++

Below are a list of sequences of numbers. Your job is to program each sequence with any loop of your preference (while, for, do/while). I want the code to output the sequence provided and the next number in the sequence (you can output more but there is 1 sequence that may only have 1 number after).. Please order and notate each sequence in your output –. The output should also be horizontal like that shown below (if you output it vertically it will be -10pts). Each sequence should be programed with only 1 loop and optionally 1 selection statement. Hint: a selection statement may be used for the last 3 problems.

Series 1:

15, 14, 13, 12, 11, ...

Series 2:

1, 2, 5, 14, 41, ...

Series 3:

2, 3, 5, 8, 12, 17, ...

Series 4:

15, 13, 11, 9, 7, ...

Series 5:

71, 142, 283, 564, 1125, 2246, 4487, 8968, ...

Series 6:

10, 5, 1, -2, -4, -5, -5, -4, -2, ...

Series 7:

0, 1, 3, 7, 15, 31, 63, ...

Series 8:

0, 1, 4, 13, 40, 121, ...

Series 9:

15, 29, 56, 108, 208, 400…

series 10: (finite)

0, 1, 3, 6, 10, 10, 11, 13, 16, 16, 17, 19, 19, ...

series 11:

7, 9, 14, 20, 27, 33, 42, 52, 63, 73, 86, ...

Series 12:

13, -21, 34, -55, 89 ...

Series 13:

0, 1, 4, 12, 32, 80, 192, ...

Answer 1

Coding

#include <iostream>
using namespace std;
int main(){
   int j,sum;
   //Seriese 1 15, 14, 13, 12, 11, ...
cout<<"Seriese 1"<<endl;
for(int i=15; i>=10; i--){
cout<<i<<",";
}
cout<<endl<<"Seriese 2"<<endl;
sum=3;
j=0;
cout<<"1"<<","<<"2"<<",";
for(int i=2; i<=41;){
   j=i+sum;      
       cout<<j<<",";
       sum=sum*3;
       i=j;
}

cout<<endl<<"Seriese 3"<<endl;
j=0;
sum=2;
for(int i=0; i<=6; i++){
   sum=sum+i;
   cout<<sum<<",";
}
cout<<endl<<"Seriese 4"<<endl;
for(int i=15; i>=4; i=i-2){
   cout<<i<<",";
}

return 0;
}

output:

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