Question

1. In Python syntax, create a list of 10 numbers (any numbers). Create your list 3 times, each time using a different syntax to define the list.

1. Write a while loop that prints the numbers from 1 to 10.

2. Convert your previous loop into a for loop.

3. Rewrite your for loop to only have one number in the range.

4. Write a for loop to print out each item of your list of 10 numbers, all on the same line, separated by & (ampersand).

In the previous question, you may notice that your line of numbers ends with the &. See if you can change this to only print the last number instead of the &. Hint: You’ll need to be clever about printing the last number from within the loop to make this work.

Answer 1

CODE:

#method 1 to declare a list
numbers = [4,5,6,7,8,9,0,4,6,1]
#method 2 to declare a list which contains 10 numbers each number being 10
numbers = [10]*10
#method 3 to append 10 numbers in the list
numbers = []
numbers.append(10)
numbers.append(10)
numbers.append(10)
numbers.append(10)
numbers.append(10)
numbers.append(10)
numbers.append(10)
numbers.append(10)
numbers.append(10)
numbers.append(10)

#counting 1 to 10 using while loop
j = 0
while(j<10):
#loop runs 10 times
j += 1
#prints j on each loop
print(j)
print()
#counting 1 to 10 using for loop
for i in range(10):
#printing the numbers
print((i+1))
print()
#printing the numbers in the list
for j,i in enumerate(numbers):
#if the current number is not the last element in the list
#then it is printed with an & at the end
if(j!= len(numbers)-1):
print(i,end = "&")
else:
#otherwise just the number and then a new line
print(i)

____________________________________________

CODE IMAGES:

___________________________________________________

OUTPUT:

______________________________________________

Feel free to ask any questions in the comments section

Thank You!