A 2.90-cm-high object is situated 11.6 cm in front of a concave mirror that has a...

A 2.90-cm-high object is situated 11.6 cm in front of a concave mirror that has a radius of curvature of 11.2 cm. Calculate (a) the location and (b) the height of the image.

Expert Solution

Note that

1/f = 1/do + 1/di

where

f = focal length = r/2 = 11.2 cm/2 =     5.6   cm
do = object distance =    11.6   cm
di = image distance

Thus, solving for di,

di =    10.8   cm, in front of the mirror   [ANSWER, PART A]

Thus, the magnification, m = -di/do,

m =    -0.933333333

Thus, as
hi =    2.9   cm

And hf = m * hi, then

hf =    -2.71   cm   [or, 2.71 cm INVERTED, ANSWER TO PART B]

genius_generous answered 9 months ago

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