Question

In: Computer Science

fun main() { val stringResult = getResult("Kotlin") val intResult = getResult(100) // TODO...

fun main() {
val stringResult = getResult("Kotlin")
val intResult = getResult(100)

// TODO 2
println()
}

// TODO 1
fun <T> getResult(args: T): Int {
return 0
}

TODO 1:
Create a new generics function with the following conditions:
The function name is getResult.
Has one type of parameter.
If the attached argument is of type Int, then the value returned is the value of the argument multiplied by 5.
If the attached argument is of type String, the value returned is a character length.
If the attached argument is of type other than Int and String, then the returned value is 0.

TODO 2:
Add functions to print the values of the stringResult and intResult variables in the console.

Expert Solution

Hi,

I have written two methods one for TODO1, another for TODO2.

TODO2 method name is : printIntResult

it will just print the argument passed in it.

TODO1 it is generic method

it can take any type of argument as you can see code below.

Please find the attached code and output also , hope it will help you.

class TODO {
   public static void main(String[] args){
       int stringResult = getResult("Kotlin");
       int intResult = getResult(100);

// TODO 2
       printIntResult(stringResult);
       printIntResult(intResult);
   }

   //TODO2 method
   public static void printIntResult(int val){
       System.out.println(val);
   }

   /**
   TODO 1 - method
   this method can take any type of argument
   it will always return integer as per your requirement.
   **/
   public static int getResult(Object obj){
       if(obj instanceof Integer){
           return ((Integer)obj) * 5;
       }
       else if(obj instanceof String){
           String newString = (String)obj;
           return newString.length();
       }
       else
           return 0;
   }

}

when you will run this code :

output will be below image :

venereology answered 8 months ago

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