Question

Q1: Constraint:
Use concept of dynamic allocation for implementation

Statement:
In a class there are N students. All of them have appeared for the test. The teacher evaluated
the test and noted marks according to their roll numbers. Marks of each students has to be incremented
by 5. Print list of marks of students before and after increment.

Answer 1

Dynamic memory allocation is a feature provided during the run time of the program. In dynamic memory allocation the data are stored in the heap memory. In dynamic memory allocation for allocating a variable value we are using pointers. For this dynamic memory allocation there are some functions. These functions are:

• Malloc (): In malloc () we are allocating the specific number of bytes for a memory.
• Calloc (): In calloc () we are allocating the memory and initializing the memory as zero.
• Reaclloc (): In this we are reallocating the memory there by we can increase and decrease the size of the memory.
• Free: Here we can release the memory which has been allocated.

Since in the above question the language is not specific. I have used C language for the compliation of the code. I am attaching the code along with the screenshot of both input and output.

PROGRAM CODE :

#include <stdio.h>
#include<stdlib.h>

int main()
{
    int *arr;
    int N,i;
    int *new_array;
    
    printf(" Enter total number of students details wanted to be input :");
    scanf("%d",&N);
    
    /* allocation of memory dynamically */
    arr = (int*)malloc(N*sizeof(int));

    if(arr==NULL)
    {
        printf(" Insufficient Memory...\n");
        return 0;
    }
    printf(" Enter %d the marks of the students : \n ",N);
    for(i=0;i<N;i++)
    {
        scanf("%d",(arr+i));
               
    }
    
    printf("\n");
    printf("MARK OF STUDENTS BEFORE INCREMENTING\n");
    printf("------------------------------------\n");
    for(i=0;i<N;i++)
    {
        
        printf("The student of Roll Number %d has %d marks \n",i+1,(*(arr+i)));
    }
    
    printf("\n");
    printf("\n");
    printf("MARK OF STUDENTS AFTER INCREMENTING\n");
    printf("-----------------------------------\n");
    for(i=0;i<N;i++)
    {
        
        printf("The student of Roll Number %d has %d marks \n",i+1,(*(arr+i)+5));
    }
    return 0;
}

SCREENSHOT OF INPUT

SCREENSHOT OF OUTPUT