In: Chemistry
#3-c Post-lab exp. 24
3. Concerning the applicability of the titration method, comment on if and how you could use it to determine Ksp for the following:
c. copper (II) iodate
To measure the solubility product (Ksp) of Cu(IO3)2
When an excess of slightly soluble salt is left in contact with water, a dynamic equilibrium between the solid and the ions in solution results. In the case of copper (II) iodate in water this salt would dissolve to a very small extent according to the reaction:
Ca(IO3)2(s) <------> Ca2+(aq) + 2 IO3 -(aq)
to determine the Ksp for Ca(IO3)2(s) by calculating the concentration of either Ca2+(aq) or IO3?(aq). The balanced equilibrium as shown above and Ksp expression are shown below:
Ksp = [Ca2+] [IO3?]2
In this experiment it is much easier to calculate the concentration of IO3?(aq) and this concentration is determined by a common technique used by chemists called a titration. In a typical titration the concentration of a certain ion [in this case IO3?(aq)] is unknown and it is combined with a reagent solution whose concentration is known. Chemists refer to the known solution as the standard solution [in this case S2O32?]. Notice that the Na2S2O3 standardized solution is listed as having a concentration of 0.05xx (four decimals) in the lab procedure. It really doesn