Question

In: Statistics and Probability

You are doing a chi-square test with a 5 by 9 table of counts (that is,...

You are doing a chi-square test with a 5 by 9 table of counts (that is, 5 rows and 9 columns).

What is the degrees of freedom?

Suppose you get ?^2 = 45.23. Calculate the p-value.

Suppose that you want to see if there is association between income level (high/medium/low) and gender.

a)Write the null hypothesis.

b)Use StatCrunch to calculate the test statistic (that is, the x?2 value) and the p-value for this contingency table, which shows the income level for a random sample of adults cross classified by gender.

Low Middle High Total
Male 23 30 29 82
Female 26 28 20 74
Total 49 56 49 156

3.( YES / NO ) Based on the data in problem #2, there is a significant association between gender and income level (use significance level 0.05).

4.( YES / NO ) Based on the data in problem #2, there is a significant difference between the income levels for the two groups (males, females) (use significance level 0.01).

5.Use StatCrunch to find a 90% confidence interval to estimate the proportion of all females who have a high income level.

Solutions

Expert Solution

a)Write the null hypothesis.

Ans: Null hypothesis: There is no a significant association between row and column.

b)Use StatCrunch to calculate the test statistic (that is, the x 2 value) and the p-value for this

Ans: Suppose you get ?^2 = 45.23 and has  5 by 9 table of counts (that is, 5 rows and 9 columns). The estimated p-value for ?^2 = 45.23 at (5-1)(9-1)=32 degree of freedom is 0.0606.

2.

Null hypothesis: There is no a significant association between gender and income level

Alternative hypothesis: There is a significant association between gender and income level.

3)

Observed (O)
Low Middle High Total
Male 23 30 29 82
Female 26 28 20 74
Total 49 56 49 156
Expected ( E)
Low Middle High
Male 25.7564103 29.4359 25.75641
Female 23.2435897 26.5641 23.24359
(O-E)^2/E
Low Middle High
Male 0.29498666 0.01081 0.408476
Female 0.32687711 0.077616 0.452636

Chi=square= Sum{(O-E)^2/E}= 1.5714

p-value =0.4558.

Ans: NO: Based on the data in problem #2, there is a significant association between gender and income level (use significance level 0.05).

4)

Ans: NO: Based on the data in problem #2, there is a significant difference between the income levels for the two groups (males, females) (use significance level 0.01).

5)


Related Solutions

When we run a chi-square test of independence on a 2x2 table, the resulting Chi-square test...
When we run a chi-square test of independence on a 2x2 table, the resulting Chi-square test statistic would be equal to the square of the Z-test statistic from the Z-test of two independent proportions. True or false
Please Perform one Chi-square Test by doing the following (Hint: Chapter 15/17, Nonparametric Methods: Chi-Square): a....
Please Perform one Chi-square Test by doing the following (Hint: Chapter 15/17, Nonparametric Methods: Chi-Square): a. Organize the data and show in MS Excel (5 points); b. Write down one potential question that you could answers using Chi-square test with the Happiness_2011.xls dataset  and state its null and alternate hypotheses (5 points); c. Perform one Nonparametric Methods: Chi-Square Test using any two reasonable variables from the Happiness_2011.xls dataset (two qualitative variables) and show the analysis results for the question (10 points);...
Please Perform one Chi-square Test by doing the following (Hint: Chapter 15/17, Nonparametric Methods: Chi-Square): a....
Please Perform one Chi-square Test by doing the following (Hint: Chapter 15/17, Nonparametric Methods: Chi-Square): a. Organize the data and show in MS Excel (5 points); b. Write down one potential question that you could answers using Chi-square test with the Happiness_2011.xls dataset and state its null and alternate hypotheses (5 points); c. Perform one Nonparametric Methods: Chi-Square Test using any two reasonable variables from the Happiness_2011.xls dataset (two qualitative variables) and show the analysis results for the question (10...
Which of the following interpretations of a Chi-square test is CORRECT? (you may use the table...
Which of the following interpretations of a Chi-square test is CORRECT? (you may use the table below as reference). a. Assume that a Chi-square test was conducted to test the goodness of fit to a 3:1 ratio and that a Chi-square value of 2.62 was obtained. The null hypothesis should be accepted. b. With the test of a 3:1 ratio, there are two degrees of freedom. c. The larger the Chi-square value, the more likely your results are real. d....
Choose either the Chi Square Goodness of Fit test OR the Chi Square Test for Independence....
Choose either the Chi Square Goodness of Fit test OR the Chi Square Test for Independence. Give an example of a research scenario that would use this test, including your hypothesis AND what makes the test suitable for your variables chosen
Janna is doing a chi-square test to see if people in California have the same color...
Janna is doing a chi-square test to see if people in California have the same color preferences as people in Nevada. A sample of 100 Californians were polled. Thirty-five people prefer yellow, fifty people prefer green, and fifteen people prefer red. A sample of 50 people from Nevada were polled. Ten people prefer yellow, ten people prefer green, and thirty people prefer red. Calculate the test statistic. State the critical value. Come to a conclusion about the null hypothesis. And...
Victoria is doing a chi-square test to see if people in California have the same color...
Victoria is doing a chi-square test to see if people in California have the same color preferences as people in Arizona. A sample of 100 Californians were polled. Thirty-five people prefer yellow, fifty people prefer green, and fifteen people prefer red. A sample of 50 Arizonans were polled. Ten people prefer yellow, ten people prefer green, and thirty people prefer red. Calculate the test statistic. State the critical value. Come to a conclusion about the null hypothesis. And state what...
1. Victoria is doing a chi-square test to see if people in California have the same...
1. Victoria is doing a chi-square test to see if people in California have the same color preferences as people in Arizona. A sample of 100 Californians were polled. Thirty-five people prefer yellow, fifty people prefer green, and fifteen people prefer red. A sample of 50 Arizonans were polled. Ten people prefer yellow, ten people prefer green, and thirty people prefer red. Calculate the test statistic. State the critical value. Come to a conclusion about the null hypothesis. And state...
Victoria is doing a chi-square test to see if people in California have the same color...
Victoria is doing a chi-square test to see if people in California have the same color preferences as people in Arizona. A sample of 100 Californians were polled. Thirty-five people prefer yellow, fifty people prefer green, and fifteen people prefer red. A sample of 50 Arizonans were polled. Ten people prefer yellow, ten people prefer green, and thirty people prefer red. Calculate the test statistic. State the critical value. Come to a conclusion about the null hypothesis. And state what...
Victoria is doing a chi-square test to see if people in California have the same color...
Victoria is doing a chi-square test to see if people in California have the same color preferences as people in Arizona. A sample of 100 Californians were polled. Thirty-five people prefer yellow, fifty people prefer green, and fifteen people prefer red. A sample of 50 Arizonans were polled. Ten people prefer yellow, ten people prefer green, and thirty people prefer red. Calculate the test statistic. State the critical value. Come to a conclusion about the null hypothesis. And state what...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT