In: Math
Gun Murders - Texas vs California - Significance Test: California had stricter gun laws than Texas. However, California had a greater proportion of gun murders than Texas. Here we test whether or not the proportion was significantly greater in California. A significant difference is one that is unlikely to be a result of random variation.
The table summarizes the data for each state. The p̂'s are actually population proportions but you should treat them as sample proportions.
The standard error (SE) is given to save calculation time if you are not using software. Data Summary number of total number Proportion State gun murders (x) of murders (n) p̂
California 1220 1786 0.68309
Texas 699 1084 0.64483
SE = 0.01812
The Test: Test the claim that the proportion of gun murders was significantly greater in California than Texas in 2011. Use a 0.05 significance level.
(a) Letting p̂1 be the proportion of gun murders in California and p̂2 be the proportion from Texas, calculate the test statistic using software or the formula z = (p̂1 − p̂2) − δp SE where δp is the hypothesized difference in proportions from the null hypothesis and the standard error (SE) is given with the data. Round your answer to 2 decimal places. z = To account for hand calculations -vs- software, your answer must be within 0.01 of the true answer.
(b) Use software or the z-table to get the P-value of the test statistic. Round to 4 decimal places. P-value =
(c) What is the conclusion regarding the null hypothesis? reject H0 fail to reject H0
(d) Choose the appropriate concluding statement.
The data supports the claim that the proportion of gun murders was significantly greater in California than Texas.
While the proportion of gun murders in California was greater than Texas, the difference was not great enough to be considered significant.
We have proven that the stricter gun laws in California actually increased the proportion of gun murders