In: Math
Two plots at Rothamsted Experimental Station were studied for production of wheat straw. For a random sample of years, the annual wheat straw production (in pounds) from one plot was as follows.
6.19 | 6.33 | 6.61 | 6.82 | 7.31 | 7.18 |
7.06 | 5.79 | 6.24 | 5.91 | 6.14 |
Use a calculator to verify that, for this plot, the sample
variance is s2 ≈ 0.272.
Another random sample of years for a second plot gave the following
annual wheat production (in pounds).
6.12 | 6.82 | 7.80 | 8.15 | 7.22 | 5.58 | 5.47 | 5.86 |
Use a calculator to verify that the sample variance for this
plot is s2 ≈ 1.052.
Test the claim that there is a difference (either way) in the
population variance of wheat straw production for these two plots.
Use a 5% level of signifcance.
(a) What is the level of significance?
State the null and alternate hypotheses.
Ho: σ12 = σ22; H1: σ12 > σ22
Ho: σ12 > σ22; H1: σ12 = σ22
Ho: σ22 = σ12; H1: σ22 > σ12
Ho: σ12 = σ22; H1: σ12 ≠ σ22
(b) Find the value of the sample F statistic. (Use 2
decimal places.)
What are the degrees of freedom?
dfN | |
dfD |
What assumptions are you making about the original distribution?
The populations follow independent normal distributions.
The populations follow independent normal distributions. We have random samples from each population.
The populations follow independent chi-square distributions. We have random samples from each population.
The populations follow dependent normal distributions. We have random samples from each population.
(c) Find or estimate the P-value of the sample test
statistic. (Use 4 decimal places.)
p-value > 0.200
0.100 < p-value < 0.200
0.050 < p-value < 0.100
0.020 < p-value < 0.050
0.002 < p-value < 0.020
p-value < 0.002
(d) Based on your answers in parts (a) to (c), will you reject or
fail to reject the null hypothesis?
At the α = 0.05 level, we reject the null hypothesis and conclude the data are not statistically significant.
At the α = 0.05 level, we reject the null hypothesis and conclude the data are statistically significant.
At the α = 0.05 level, we fail to reject the null hypothesis and conclude the data are not statistically significant.
At the α = 0.05 level, we fail to reject the null hypothesis and conclude the data are statistically significant.
(e) Interpret your conclusion in the context of the
application.
Fail to reject the null hypothesis, there is sufficient evidence that the variance in annual wheat production differs between the two plots.
Reject the null hypothesis, there is insufficient evidence that the variance in annual wheat production differs between the two plots.
Reject the null hypothesis, there is sufficient evidence that the variance in annual wheat production differs between the two plots.
Fail to reject the null hypothesis, there is insufficient evidence that the variance in annual wheat production differs between the two plots.
Values ( X ) | Σ ( Xi- X̅ )2 | Values ( Y ) | Σ ( Yi- Y̅ )2 | |
6.19 | 0.1007 | 6.12 | 0.2576 | |
6.33 | 0.0314 | 6.82 | 0.0371 | |
6.61 | 0.0105 | 7.8 | 1.3748 | |
6.82 | 0.0978 | 8.15 | 2.318 | |
7.31 | 0.6443 | 7.22 | 0.3511 | |
7.18 | 0.4525 | 5.58 | 1.0973 | |
7.06 | 0.3055 | 5.47 | 1.3398 | |
5.79 | 0.5145 | 5.86 | 0.5891 | |
6.24 | 0.0714 | |||
5.91 | 0.3568 | |||
6.14 | 0.1349 | |||
Total | 71.58 | 2.7203 | 53.02 | 7.3648 |
Mean X̅ = Σ Xi / n
X̅ = 71.58 / 11 = 6.5073
Sample Standard deviation SX = √ ( (Xi - X̅ )2 / n - 1
)
SX = √ ( 2.7203 / 11 -1 ) = 0.5216
Sample Variance = 0.52162= 0.272
Mean Y̅ = ΣYi / n
Y̅ = 53.02 / 8 = 6.6275
Sample Standard deviation SY = √ ( (Yi - Y̅ )2 / n - 1
)
SY = √ ( 7.3648 / 8 -1) = 1.0257
Sample Variance = 1.02572 = 1.052
Part a)
α = 0.05
Ho: = σ22; H1: σ12 ≠ σ22
Part b)
Test Statistic :-
f = 0.272 / 1.052
f = 0.26
Degree of freedom
n1 - 1 = 11 - 1 = 10
n2 = 8 - 1 = 7
The populations follow independent normal distributions.
Part c)
P value = 2 * P ( f > 0.2586 ) = 0.0534
0.050 < p-value < 0.100
Part d)
Reject null hypothesis if P value < α = 0.05
Since P value = 0.0534 > 0.05, hence we fail to reject the null
hypothesis
Conclusion :- We Fail to Reject H0
At the α = 0.05 level, we fail to reject the null hypothesis and conclude the data are not statistically significant.
Part e)
Fail to reject the null hypothesis, there is insufficient evidence that the variance in annual wheat production differs between the two plots.