Question

An amateur meteorologist wants to keep track of weather conditions during the past year's three -month summer season and has designated each day as either rainy ('R'), cloudy ('C'), or sunny ('S'). Write a modu lar program that stores this information in a 3 x 30 array of characters, where the row indicates the month (0 = June, 1 = July, 2 = August) and the column indicates the day of the month. Note that data is not being collected for the 31st of any month . The program should begin by calling a function to read the weather data in from a file. Then it should create a report that displays for each month and for the whole three-month period, how many days were rainy, how many were cloudy, and how many were sunny. To help it do this, it should use a value -returning function that is passed the array, the number of the month to examine, and the character to look for ('R', 'C', or 'S') . This function shou ld return the number of days the indicated month had the requested weather. Data for the program can be found in the Rai nOrShi ne. da t file located in the Chapter 8 programs folder on this book's companion website. please do this program in c++ and please add comments.

Answer 1

C++ Program :

#include <iostream>
using namespace std;

//This function helps in reading the weather data from the file RainOrShine.dat
//I have assumed that the file contains data in the following format as it was not specified
//in the question:
//RRRRSSSS...CCR ---> representing days of june
//RRRRSSSS...CCR ---> representing days of july
//RRRRSSSS...CCR ---> representing days of august

void readFromFile(char *weatherData[3]){
    string line;
    ifstream myfile("RainOrShine.dat");
    if(myfile.is_open()){
        int month = 0;
        while(getline(myfile,line)){
            for(int i=0;i<30;i++){
                weatherData[month][i] = line[i];
            }
            month++;
        }
        myfile.close();
    }else{
        cout<<"Unable to open data file"<<endl;
    }
}

//This is the helper function which accepts the monthNumber and the condition of the
//day to be looked for i.e. whether rainy,cloudy or sunny and returns the number of
//days in that month having that condition.

int analysis(char *weatherData[3],int monthNumber,char condition){
    int ans = 0;
   for(int i=0;i<30;i++){
       if(weatherData[monthNumber][i] == condition)ans++;
   }
   return ans;
}  

int main() {
  
    char *weatherData[3];
  
    for(int i=0;i<3;i++){
        weatherData[i] = new char[30];  
    }
  
    //Now we have a 2d character array of size 3x30
  
  
    //This reads the file and stores the data into the char array
    readFromFile(weatherData);
  
  
    //Output for june
    cout<<"FOR JUNE:\n";
    cout<<"Number of rainy days: "<<analysis(weatherData,0,'R')<<endl;
    cout<<"Number of sunny days: "<<analysis(weatherData,0,'S')<<endl;
    cout<<"Number of cloudy days: "<<analysis(weatherData,0,'C')<<endl;
    cout<<endl;
  
  
  
    //Output for july
    cout<<"FOR JULY:\n";
    cout<<"Number of rainy days: "<<analysis(weatherData,1,'R')<<endl;
    cout<<"Number of sunny days: "<<analysis(weatherData,1,'S')<<endl;
    cout<<"Number of cloudy days: "<<analysis(weatherData,1,'C')<<endl;
    cout<<endl;
  
  
  
    //Output for august
    cout<<"FOR AUGUST:\n";
    cout<<"Number of rainy days: "<<analysis(weatherData,2,'R')<<endl;
    cout<<"Number of sunny days: "<<analysis(weatherData,2,'S')<<endl;
    cout<<"Number of cloudy days: "<<analysis(weatherData,2,'C')<<endl;
   return 0;
  
  
}