A sample of college students was asked how much they spent monthly on pizza. Approximate the...

A sample of college students was asked how much they spent monthly on pizza. Approximate the standard deviation for the cost.

Monthly pizza cost. total number of students

10.99-19.99 7

20.99-29.99 20

30.99-39.99 23

40.99-49.99 20

50.99-59.99 5

The sample standard deviation for the cost is (round to nearest cent)

Expert Solution

Solution:

First we will calculate mean

Mean = summation(f*Midpoints)/summation(f) = (108.43+509.8+816.27+909.8+277.45)/(7+20+23+20+5) = 2621.75/75 = 34.96

Standard deviation can be calculated as

Standard deviation = Sqrt(summation(f*(midpoints-Mean)^2)/f-1)) = Sqrt(2653.5663+1793.618+6.6407+2217.618+2107.4045)/74( = Sqrt(118.63) = 10.88

orchestra answered 2 years ago

A sample of college students was asked how much they spent monthly on coffee. Approximate the...

A sample of college students was asked how much they spent monthly on coffee. Approximate the standard deviation for the cost. Monthly coffee cost ($) Number of students 10.00-19.99 6 20.00-29.99 20 30.00-39.99 . 23 40.00-49.99 18 50.00-59.99 . 6 The sample standard deviation for the cost is (Round to the nearest cent as needed.)

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