Use a recursion tree to determine a good asymptotic upper bound
on the following recurrences. Use the substitution method to verify
your answer.
T(n) = 3T(n/2) + n.
T(n) = T(n/2) + n2.
Use a recursion tree to determine a good asymptotic upper bound
on the recurrence ?(?) = 3?(?/3) + ?. Use the substitution method
to verify your answer.
Use a recursion tree to determine a good asymptotic upper bound
on the recurrence T(n) = 2T(n/3) + 2n.
Use the substitution method to verify your answer
Give asymptotic tight bounds for T(n) in each of the following
recurrences using recursion tree.
a. T(n) = 2T(n − 1) + 1
b. T(n) = t(n − 1) + n
c. T(n) = 2T (n/4) + √n
Solve the following recurrence relations: (find an asymptotic
upper bound O(?) for each one)
a. T(n) = T(2n/3)+T(n/3) + n^2
b. T(n) = √nT(√n) + n
c. T(n) = T(n-1)+T(n/2) + n
The base case is that constant size problems can be solved in
constant time (O(1)). You can use the induction, substitution or
recursion tree method
Use the recursion tree method to determine the asymptoticupper
bound of T(n).T(n) satisfies the recurrence T(n)=2T(n-1)+ c, where
c is a positive constant, andT(0)=0.
Given the integral 1/x dx upper bound 2 lower bound 1
(a) use simpson's rule to approximate the answer with n=4
Formula:f(x)=1/3[f(x0)+4f(x1)+2f(x2)+...+f(xn)]Δx(keep answer to
6 decimals)
b)how large is n in order for the error of Simpsons rule for the
given integral is no more than 0.000001
Formula: |Es|=(k)(b-a)^5/(180 n^4), where |f^4(x)≤k|
please show all work and steps
Recall the following theorem, phrased in terms of least upper
bounds.
Theorem (The Least Upper Bound Property of R). Every nonempty
subset of R that
has an upper bound has a least upper bound.
A consequence of the Least Upper Bound Property of R is the
Archimedean Property.
Theorem (Archimedean Property of R). For any x; y 2 R, if x > 0,
then there exists
n 2 N so that nx > y.
Prove the following statements by using...
Derive a Θ-bound on the solution to the following recurrence.
using iterative recursion and check your answer with master theorem
result
T(n) = T (1/3 n) + log n