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10.5 mL of 0.100M ammonium chloride aqueous solution is titrated with 0.100 M NaOH(aq). What type...

10.5 mL of 0.100M ammonium chloride aqueous solution is titrated with 0.100 M NaOH(aq).

What type of solution is present when VNaOH = 20.00 mL?

Select one:

a. strong acid

b. strong base

c. weak acid

d. weak base

e. buffered

Solutions

Expert Solution

answer : b. strong base

NH4Cl    + NaOH ----------------------> NH4OH + NaCl

10.5 x0.1      20 x0.1                              0             0

1.05             2                                          0              0    ----------------initial

0                 0.95                                    0.95         0.95       -------------equlibrium

NaOH remained millimoles =0.95

[OH-] = 0.95/total volume

           =0.95/(10.5+20)

          = 0.031

pOH = -log[OH-]= -log(0.031)= 1.5

pH+ pOH= 14

pH = 14-pOH

pH= 12.5

so this pH indicate strong base

queen_honey_blossom answered 4 days ago
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