Question

1. Convert a list of decimal numbers into their binary and hexadecimal equivalents
2. Add the elements of each of these lists to generate a total sum
3. Print the lists, and the total sum of each value

C++ contains some built-in functions (such as itoa and std::hex) which make this assignment trivial. You may NOT use these in your programs. You code must perform the conversion through your own algorithm.

The input values are:

5

9

24

2

39

83

60

8

11

10

6

18

31

27

Answer 1

#include<iostream>
using namespace std;
//method to convert to binary
int toBinary(int n)
{
   if(n==0)
   return 0;
   return toBinary(n/2)*10 + n%2;
}
//method to convert number to hexadecimal
string toHex(int n)
{
   char c[] = {'0','1','2','3','4','5','6','7','8','9','A','B','C','D','E','F'};
   if(n==0)
   return "";
   return toHex(n/16)+ ""+c[n%16];
}
int main()
{
   int n;
   cout<<"Enter how many number u want to enter:";
   cin>>n;
   cout<<"Enter numbers:";
   int m,i=1;
   while(i<=n)
   {
       cout<<i<<":";
       cin>>m;
       cout<<"Binary :"<<toBinary(m)<<endl;  
       cout<<"Hexadecimal :"<<toHex(m)<<endl;
       i++;
   }
  
   return 0;
}

output:

Enter how many number u want to enter:14
Enter numbers:1:5
Binary :101
Hexadecimal :5
2:9
Binary :1001
Hexadecimal :9
3:24
Binary :11000
Hexadecimal :18
4:2
Binary :10
Hexadecimal :2
5:39
Binary :100111
Hexadecimal :27
6:83
Binary :1010011
Hexadecimal :53
7:60
Binary :111100
Hexadecimal :3C
8:8
Binary :1000
Hexadecimal :8
9:11
Binary :1011
Hexadecimal :B
10:10
Binary :1010
Hexadecimal :A
11:6
Binary :110
Hexadecimal :6
12:18
Binary :10010
Hexadecimal :12
13:31
Binary :11111
Hexadecimal :1F
14:27
Binary :11011
Hexadecimal :1B

Process exited normally.
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