Question

In C++

Write a function called findMatchedGenome that takes three genomes and a sequence and prints the list of matched genomes

• The function must be named findMatchedGenome
• The function will take in 4 string input parameters in the order
  • Genome 1, a string
  • Genome 2, a string
  • Genome 3, a string
  • sequence (sub-sequence of the genomes), a string
• The function should not return anything.
• Unexpected values might be passed into a function and your function should be able to handle it without crashing the program:
  • If one or more genomes or sequence is an empty string, then it prints “Genomes or sequence is empty.” Function will exit.
  • If the length of the three genomes is different, it prints “Lengths of genomes are different.” Function will exit.

Checking these cases must be performed in the order specified above. First check for empty genomes and sequence followed by a check for different lengths.

Helper functions (the functions used in your findMatchedGenome) should be written in the answer box as well.

For example:

Test	Result
//For empty sequence findMatchedGenome("TTC","GCC","TCT","");	Genomes or sequence is empty.

Answer 1

Note: Could you plz go through this code and let me know if u need any changes in this.Thank You
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#include <iostream>
#include <string>
#include <iomanip>

using namespace std;

void findMatchedGenome(string genome1,string genome2,string genome3,string seq);
int main(void) {
   //Declaring variables
findMatchedGenome("TTC","GCC","TCT","");  
   return 0;
}
void findMatchedGenome(string genome1,string genome2,string genome3,string seq)
{
   if(genome1.compare("")==0 || genome2.compare("")==0||genome3.compare("")==0|| seq.compare("")==0)
   {
       cout<<"Genomes or sequence is empty."<<endl;
   }
   else if(genome1.length()!=genome2.length() ||
   genome2.length()!=genome3.length() ||
           genome3.length()!=genome1.length())
           {
               cout<<"Lengths of genomes are different."<<endl;
           }
           else
           {
               if(genome1.compare(seq)==0)
               {
                   cout<<"Genome1 is matched to sequence."<<endl;
               }
               else if(genome2.compare(seq)==0)
               {
                   cout<<"Genome2 is matched to sequence."<<endl;
               }
               else if(genome3.compare(seq)==0)
               {
                   cout<<"Genome3 is matched to sequence."<<endl;
               }
               else
               {
                   cout<<"No Genome is matched to sequence."<<endl;
               }
              
           }
}

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Output:

____________________________Thank You