Question

JAVA:

Compute the average of a list of user-entered integers representing rolls of two dice. The list ends when 0 is entered. Integers must be in the range 2 to 12 (inclusive); integers outside the range don't contribute to the average. Output the average, and the number of valid and invalid integers (excluding the ending 0). If only 0 is entered, output 0. The output may be a floating-point value. Ex: If the user enters 8 12 13 0, the output is:

Average: 10
Valid: 2
Invalid: 1

Hints:

• Use a while loop with expression (userInt != 0).

• Read the user's input into userInt before the loop, and also at the end of the loop body.

• In the loop body, use an if-else to distinguish integers in the range and integers outside the range.

• For integers in the range, keep track of the sum, and number of integers. For integers outside the range, just keep track of the number.

• Use a cast to get a floating-point output: (double) sum / num .

• Whenever dividing, be sure to handle the case of the denominator being 0.

Answer 1

SOLUTION-
I have solve the problem in Java code with screenshot for easy understanding :)

CODE-

//java code

import java.util.Scanner;

public class Main {
   public static void main(String[] args) {
       Scanner scnr = new Scanner(System.in);
       int sum = 0;
       int validCount = 0, invalidCount = 0;
       float avg;
       int userInt = scnr.nextInt();
       while (userInt != 0) {
           if (userInt >= 2 && userInt <= 12) {
               sum += userInt;
               validCount++;
           } else {
               invalidCount++;
           }
           userInt = scnr.nextInt();
       }
       if (validCount == 0) {
           System.out.println("Average: 0");
       } else {
           avg = (float) sum / validCount;
           System.out.println("Average: " + avg + " Valid: " + validCount + " Invalid: " + invalidCount);
       }
       scnr.close();
   }
}

SCREENSHOT-

Sample output 1:

Sample output 2:

Sample output 3:

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