Question

Write a java program that lets the user to enter any two integers and weave them digit by digit and print the result of weaving their digits together to form a single number. Two numbers x and y are weaved together as follows. The last pair of digits in the result should be the last digit of x followed by the last digit of y. The second-to-the-last pair of digits in the result should be the second-to- the-last digit of x followed by the second-to-the-last digit of y. And so on.

You should write weaveNumber method that works as following examples weaveNumber( 271 ,389).should return 237819. If one of the numbers has more digits than the other, you should imagine that leading zeros are used to make the numbers of equal length. For example, weaveNumber(2384, 12) should return 20308142 (as if it were a call on weaveNumber(2384, 0012)). Similarly, weaveNumber(9, 318) should return 30198 (as if it were a call on weaveNumber(009, 318)).

Answer 1

Complete java program:

import java.util.Scanner;
public class WeaveNumberFinder {

   public static void main(String[] args) {
       //Scanner class object to read inputs
       Scanner scan = new Scanner(System.in);
      
       //asking inputs
       System.out.print("Enter first integer:");
       int num1 = scan.nextInt();
       System.out.print("Enter second integer:");
       int num2 = scan.nextInt();
      
       //calling weaveNumber() method
       int weaveNum = weaveNumber(num1,num2);
       System.out.println("Weave number:"+weaveNum);
   }
  
   //method implementation
   public static int weaveNumber(int num1,int num2) {
      
       //convert two numbers to two different strings
       String numStr1 = String.valueOf(num1);
       String numStr2 = String.valueOf(num2);
      
       StringBuilder sb1= new StringBuilder();
       StringBuilder sb2= new StringBuilder();
       String finalString = new String();
      
       int diffDigits=0;
       if(numStr1.length() > numStr2.length()) {
           //find out the difference of digits
           diffDigits = numStr1.length() - numStr2.length();
          
           //append diffDigits number of '0' to the sb2
           for(int i=1;i<=diffDigits;i++) {
               sb2.append("0");
           }
          
           //append all digits of num2 to sb2
           for(int i=0;i<numStr2.length();i++) {
               sb2.append(numStr2.charAt(i));
           }

           //preparing final string-concatenating both strings
           for(int i=0;i<numStr1.length();i++) {
               finalString = finalString +numStr1.charAt(i)+ sb2.charAt(i);
           }
       }else if(numStr2.length() > numStr1.length()) {
          
           //find out the difference of digits
           diffDigits = numStr2.length() - numStr1.length();
          
           //append diffDigits number of '0' to the sb1
           for(int i=1;i<=diffDigits;i++) {
               sb1.append("0");
           }
           //append all digits of num1 to sb1
           for(int i=0;i<numStr1.length();i++) {
               sb1.append(numStr1.charAt(i));
           }
          
           //preparing final string-concatenating both strings
           for(int i=0;i<numStr2.length();i++) {
               finalString = finalString+ sb1.charAt(i)+numStr2.charAt(i);
           }
       }else {
           //if both numbers have equal number of digits
          
           //preparing final string-concatenating both strings
           for(int i=0;i<numStr1.length();i++) {
               finalString = finalString+numStr1.charAt(i)+ numStr2.charAt(i);
           }
       }
      
       //converting string to int and return the same value to main
       return Integer.parseInt(finalString);
   }
}
Output: