Question

In: Physics

l

Expert Solution

The above derivation will help us to solve the first and second part, since in both the cases gain is negative hence we have to use an inverting amplifier configuration.

1) Rif = 20k ohms to be designed for this case

Which means value of R1 || (internal resistance ) = 20k

R1 || 5Mohms = 20k

R1*5*10^(6)/ (R1 + 5*10^(6)) = 20k

5*10^(6)*R1 = 20*10^3*R1 + 10^11

R1(5*10^(6) - 20*10^(3)) = 10^(11)

R1 = 20.08 K ohms

Now gain equation

75 = R2/( R1 + 1/A*(R1 + R2))

75 = R2/ (20.08k + 1/A*(20.08k + R2)

75*20.08k + 75/A*20.08k = R2 - 75/A*R2

R2 = 1506677.09502 ohms = 1.506677 M ohms

2)

Rif = 50k ohms to be designed for this case

Which means value of R1 || (internal resistance ) = 50k

R1 || 5Mohms = 50k

R1*5*10^(6)/ (R1 + 5*10^(6)) = 50k

5*10^(6)*R1 = 50*10^3*R1 + 2.5*10^11

R1(5*10^(6) - 50*10^(3)) = 2.5*10^(11)

R1 = 50.505 K ohms

Now gain equation

30 = R2/( R1 + 1/A*(R1 + R2))

30 = R2/ (50.505k + 1/A*(50.505k + R2)

30*50.505k + 30/A*50.505k = R2 - 30/A*R2

R2 = 1515604.09502 ohms = 1.515604 M ohms

The above derivation will help us to solve the third and fourth part, since in both the cases gain is positive hence we have to use an non-inverting amplifier configuration.

3)

Rif = 15M ohms to be designed for this case

We have to use the feedback factor for this case, the gain in the case of feedback factor will be A/(1 + AB) and Rin(1 + AB)

15M = (R1 || 5M)(1 + AB)

Af = 150 = A/(1 +AB)

(1 + AB) = 3*10^(5)/(150) = 2000

Hence we get from the first equation,

15M = (R1 || 5M)(2000)

R1 || 5M = 7.5k

R1 * 5* 10^(6)/ (R1 + 5*10^(6) = 7.5k

R1*5*10^(6) = 7.5*10^3*R1 + 5*10^(6)*7.5*10^(3)

R1 = 7511 ohms = 7.511 kohms

1 + AB = 2000

AB = 1999

B = 1999/(3*10^(5)) = 0.006663333

R1/(R1 + R2) = 0.006663333

R1 - 0.006663333R1 = 0.0006663333R2

Hence we get R2 = 1118062.37 = 1.11 M ohms

4)

Rif = 20M ohms to be designed for this case

We have to use the feedback factor for this case, the gain in the case of feedback factor will be A/(1 + AB) and Rin(1 + AB)

20M = (R1 || 5M)(1 + AB)

Af = 21 = A/(1 +AB)

(1 + AB) = 3*10^(5)/(21) = 14285.7

Hence we get from the first equation,

20M = (R1 || 5M)(14285.7)

R1 || 5M = 1.4k

R1 * 5* 10^(6)/ (R1 + 5*10^(6) = 1.4k

R1*5*10^(6) = 1.4*10^3*R1 + 5*10^(6)*1.4*10^(3)

R1 = 1400.5 ohms =1.4005 Kohms

1 + AB = 14285.7

AB = 14285.7

B = 14285.7/(3*10^(5)) = 0.047619

R1/(R1 + R2) = 0.047619

R1 - 0.047619R1 = 0.047619R2

Hence we get R2 = 28010.69 = 28.01k ohms

genius_generous answered 1 week ago

Let L ⊆ Σ ∗ and define S(L), the suffix-language of L, as S(L) = {w...

Let L ⊆ Σ ∗ and define S(L), the suffix-language of L, as S(L) = {w ∈ Σ ∗ | x = yw for some x ∈ L, y ∈ Σ ∗ } Show that if L is regular, then S(L) is also regular.

Part A) Electrolysis is performed on a mixture of CuBr(l), AgBr(l), MgBr2(l), and NiBr2(l). Which of...

Part A) Electrolysis is performed on a mixture of CuBr(l), AgBr(l), MgBr2(l), and NiBr2(l). Which of the following is produced at the cathode? A) Cu(s) B) Ag(s) C) Mg(s) D) Ni(s) Part B)You are given some ferrous iodide, FeI2 , and are asked to extract the iron through electrolysis. What can be said about the merits of molten versus aqueous FeI2 ? You are given some ferrous iodide, \rm FeI_2, and are asked to extract the iron through electrolysis. What...

A particle is bound between x = -L to x = L where L = 0.1...

A particle is bound between x = -L to x = L where L = 0.1 nm. The wave function is given by: a) Find A b) What is the probability of finding the particle between -0.05 nm and 0.05 nm?

Electrolysis is performed on a mixture of CuBr(l), AgBr(l), MgBr2(l), and NiBr2(l). Which of the following is produced at the cathode?

Electrolysis is performed on a mixture of CuBr(l), AgBr(l), MgBr2(l), and NiBr2(l). Which of the following is produced at the cathode? Br2(l) Cu(s) Ag(s) Mg(s) Ni(s)

Part A) Electrolysis is performed on a mixture of CuBr(l), AgBr(l), MgBr2(l), and NiBr2(l). Which of the following is produced at the cathode?

Part A) Electrolysis is performed on a mixture of CuBr(l), AgBr(l), MgBr2(l), and NiBr2(l). Which of the following is produced at the cathode? A) Cu(s) B) Ag(s) C) Mg(s) D) Ni(s) Part B)You are given some ferrous iodide, FeI2 , and are asked to extract the iron through electrolysis. What can be said about the merits of molten versus aqueous FeI2 ? A)You'll have to perform electrolysis on the molten salt because you can't get iron metal from electrolysis...

Calculate the hardness using the following concentrations: Na+=248mg/L K+=5.5mg/L Ca2+=54mg/L Mg2+=26mg/L

def mystery(L, x): if L==[]: return False if L[0] == x: return True L.pop(0) return mystery(L,...

def mystery(L, x): if L==[]: return False if L[0] == x: return True L.pop(0) return mystery(L, x) What is the input or length size of the function mystery? What is the final output of mystery([1,3,5,7], 0)? Explain in one sentence what mystery does? What is the smallest input that mystery can have? Does the recursive call have smaller inputs? Why? Assuming the recursive call in mystery is correct, use this assumption to explain in a few sentences why mystery is...

Prove that the dual space of l^1 is l^infinity

Suppose Noah and Naomi's short-run weekly production function for garden benches is F(L)=min{0,L−3},F(L)=min⁡{0,L−3}, where L...

Suppose Noah and Naomi's short-run weekly production function for garden benches is F(L)=min{0,L−3},F(L)=min⁡{0,L−3}, where L represents the number of hours of labor employed. The wage rate is $12 an hour. For non-negative amounts of output, what is their short-run cost function? C = 36 + 12Q. C =12 +36Q. C =12Q. C = 36Q. C =36 - 12Q.

Patient A Patient B Patient C Na+ 138 mEq/L 142 mEq/L 148 mEq/L K+ 5.1 mEq/L...

Patient A Patient B Patient C Na+ 138 mEq/L 142 mEq/L 148 mEq/L K+ 5.1 mEq/L 6.1 mEq/L 3.8 mEq/L Ca+ 8.9 mg/dL 7.5 mg/dL 9.5 mg/dL Mg+ 1.3 mg/dL 0.9 mg/dL 2.1 mg/dL pH 7.40 7.32 7.42 PCO2 42 mm Hg 48 mm Hg 40 mm Hg PO2 95% 98% 99% HCO3 22 28 26 Patient B is complaining of numbness and tingling, especially around the mouth. What are the other two electrolyte imbalances in this patient that could...