Question

Write a function named timesOfLetter that reads an array and returns the number of times of each lowercase letter and each uppercase letter appear in it, using reference parameter. • Write a function named timesOfNumber that reads an array and returns the number of times of each odd number, and each even number appear in it, using reference parameter. • Write a function named isChar() that determines if the input is alphabetic or not during inputting. • Write a function named isInt() that determines if the input is a digit or not during inputting. • Initialize the size of the arrays as 10.

Hints: • Firstly, determine whether the element is a letter or a number, which should not be any other characters. • By passing by reference, the values can be modified without returning them. • You may call a function inside another function.

Answer 1

//function named determines if the input is alphabetic or not
bool isChar(char c)
{
   if((c>='a' && c<='z') || (c>='A' && c<='Z'))
       return true;
   return false;
}

//function that determines if the input is a digit or not
bool isInt(int n)
{
   if(n>='0' && n<='9')
       return true;
   return false;
}

/* function that reads an array and returns the number of times of each
lowercase letter and each uppercase letter appear in it, using reference
parameter.
nl = number of lowercase, nu = number of uppercase
*/
void timesOfLetter(int &nl, int &nu)
{
   char s[10], ch;
int n = 10;
  
   for(int i=0; i<n; i++)
   {
       cin>>ch;
       if(isChar(i)==false)
       {
           cout<<"Not a letter!";
           i--;
           continue;
       }
       s[i] = ch;
   }
      
   nl = nu = 0;
  
   for(int i=0; i<n; i++)
   {
       if(s[i]>='a' && s[i]<='z') nl++;
       else if(s[i]>='A' && s[i]<='Z') nu++;
   }
}

/* function that reads an array and returns the number of times of each odd
number, and each even number appear in it, using reference parameter.
ne = number of even, no = number of odd
*/
void timesOfNumber(int &ne, int &no)
{
   int s[10], a;
   int n = 10;
  
   for(int i=0; i<n; i++)
   {
       cin>>a;
       if(isInt(i)==false)
       {
           cout<<"Not a digit!";
           i--;
           continue;
       }
       s[i] = a;
   }
  
   ne = no = 0;
  
   for(int i=0; i<n; i++)
   {
       if(s[i]%2==0) ne++;
       else no++;
   }
}