In: Chemistry
The 1s--> 2p transition in a hydrogen-like ion occurs at
7.10704x105 cm-1
.
a. What is the ionization energy of this atom in Joules?
b. If this atom is ionized with light with a wavelength 4.00 nm,
what is the de Broglie
wavelength of the ejected electrons?
a) Given frequency = 7.10*10 5 cm-1
E = hc(wave number) = 6.626*10-34 J.sec * 3*108 m/sec * 7.10*103 m-1 = 1.41*10-21 J(ionization energy)
b) For the given wave length , energy associated = E = hc/wave length
= (6.626*10-34 J.sec) (3*108 m/sec) / 4*10-9 m
= 4.96*10-17 J
Thus , K.E of ejected electrons = -1.41*10-21 + 4.96*10-17 = 4.96*10-17
deBroglie's wave length = h / (2*m*KE)1/2 = 6.626*10-34 / (2*4.96*10-17* 9.1*10-31 kg)1/2
= 0.0696 nm