Question

In: Physics

A toy train takes 3 minutes to run one and a half times around a circular...

A toy train takes 3 minutes to run one and a half times around a circular track with a circumference of 5.7 m. The difference between its average speed and the magnitude of its average velocity for the one and a half laps is

Solutions

Expert Solution

Solution:

Distance of the circular track= circumference = 5.7 m

Distance covered by the toy train in 3 minutes = one and half circular track * circumference

= 1 1/2 * 5.7m

= 3/2 * 5.7 m

= 8.55m

Time taken to cover one and a half circular track = 3 minutes=180 sec

Now to find average speed and average velocity for one and a half laps .

One laps means one full circle of the track.An example of a laps is one run around a track.

Here one and a half laps means one and a half times around a circular track=8.55m

Formula to find average speed

Average speed = Total distance/total time taken

Average speed to cover one and a half laps = total distance/ total time

= 8.55 m/180 sec

   =0.0475 m/s

Now to find average velocity

Average velocity = Displacement/ total time taken

Here displacement means it is the straight line distance from the initial position to the final position.Its a vector quantity(has both magnitude and direction).

Since the toy train starts at point A and after completing one and a half laps the toy train reaches point B ,which is the exact opposite point of A .Thus the displacement of the toy train after covering one and a half laps will be the diameter of the circle( as initial point is A and final point id B).

  

Thus the dispalcement is diameter of the circle or twice the radius.

Now inorder to find displacement we need to find radius.For that we can use formula

circumference = 2*π * R where R = radius

= 2* 3.14* R π = 3.14

We know circumference = 5.7m.On substituting we get;

5.7 = 2* 3.14* R

R= 5.7/(2* 3.14) =5.7/6.28

R= 0.9076 m

Thus dispalcement = diameter= 2* radius = 2* 0.9076 m = 1.81528 m

Average velocity = Displacement /total time taken to complete one and half laps

= 1.81528 /180 sec

Average velocity= 0.01008 m/sec

NOW we got average speed =0.0475 m/s and Average velocity =0.01008 m/sec

The difference between average speed and average velocity = 0.0475 - 0.01008

= 0.03742 m/s

Thus we can conclude that when a toy train is moving in a circular track of radius 0.9076 m its average speed will be more than average velocity by a value of 0.03742m/s.

NOTE: Average velocity will never be greater than average speed in any situation.It can be equal in some situation but never greater than average speed.


Related Solutions

A satellite in a circular orbit around the earth with a radius 1.011 times the mean...
A satellite in a circular orbit around the earth with a radius 1.011 times the mean radius of the earth is hit by an incoming meteorite. A large fragment (m = 81.0 kg) is ejected in the backwards direction so that it is stationary with respect to the earth and falls directly to the ground. Its speed just before it hits the ground is 361.0 m/s. Find the total work done by gravity on the satellite fragment. RE 6.37·103 km;...
Suppose we have collected times, in minutes, that it takes volunteers to complete a set of...
Suppose we have collected times, in minutes, that it takes volunteers to complete a set of pencil and paper mazes. Volunteers are randomly assigned to one of two groups. Group 1 watch a 5 minute video explaining good strategies for completing the mazes. Group 2 watch a 5 minute video of other people successfully completing the mazes, but with no explanation given. Researchers are interested in testing against the null hypothesis that there is no difference in population mean times...
Suppose we have collected times, in minutes, that it takes volunteers to complete a set of...
Suppose we have collected times, in minutes, that it takes volunteers to complete a set of pencil and paper mazes. Volunteers are randomly assigned to one of two groups. Group 1 watch a 5 minute video explaining good strategies for completing the mazes. Group 2 watch a 5 minute video of other people successfully completing the mazes, but with no explanation given. Researchers are interested in testing against the null hypothesis that there is no difference in population mean times...
    It takes a barber 15 minutes to serve one customer.   a. What is...
    It takes a barber 15 minutes to serve one customer.   a. What is the capacity of the barber expressed in customers per hour?   customers per hour         b. Assuming the demand for the barber is 2 customers per hour, what is the flow rate?   customers per hour         c. Assuming the demand for the barber is 2 customers per hour, what is the utilization?   percent      ...
A concrete walk 3 feet wide is placed around the outside of a circular pond with...
A concrete walk 3 feet wide is placed around the outside of a circular pond with diameter 15 feet. What is the total cost of the walk if the cost per square foot is $1.31
Consider results of 20 randomly chosen people who have run a marathon. Their times, in minutes,...
Consider results of 20 randomly chosen people who have run a marathon. Their times, in minutes, are as follows: 137, 146, 150, 163, 166, 179, 186, 193, 196, 213, 218, 225, 236, 239, 254, 269, 271, 279, 282, 295. Calculate a 90% upper confidence bound on the mean time of the race. Assume distribution to be normal.
Question 3: Train Co. utilizes process costing for its main product, toy trains. Data relating to...
Question 3: Train Co. utilizes process costing for its main product, toy trains. Data relating to toy trains processed in Department 1, Moulding, during August are presented as follows: Toy Trains Percentage Completed* Work in Process, beginning 40,000 70% Started into Process during Period 60,000 Work in Process, ending 20,000 30% * relates to conversion costs * related to conversion costs Materials are added at the beginning of the process in Department 1. Costs in beginning work in process inventory...
A spy satellite is in circular orbit around Earth. It makes one revolution in 6.10 h....
A spy satellite is in circular orbit around Earth. It makes one revolution in 6.10 h. Mass of Earth is 5.974 × 1024 kg, radius of Earth is 6371 km and Gravitational constant G is = 6.674 × 10−11 N·m2/kg2. 1. How high above Earth’s surface is the satellite? _____km 2.What is the satellite’s acceleration? _____ m/s^2
one afternoon a couple walks 7/8 of the way around a circular lake, the radius of...
one afternoon a couple walks 7/8 of the way around a circular lake, the radius of which is 1.65km. they start at the west side of the lake and the head die south to begin with. a. what is the distance they travelled? b. what are the magnitude and direction (relative to due east) of the couples displacment?
Question 3. It takes an average of 55 minutes to fly from YYZ to New York’s...
Question 3. It takes an average of 55 minutes to fly from YYZ to New York’s JFK airport, averaged across all airlines. The variance of all flights is 49 minutes. Sixty percent of passengers tend to be male. 3a. A new airline is hoping to reduce this flight time. They will use the same variance and standard deviation as its measure of variability. Explain why this is a statistically valid method. 3b. It takes an average of 58 minutes to...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT