Question

USE R

2520 is the smallest number that can be divided by each of the numbers from 1 to 10 without any remainder. Now you need to create a function to find the smallest positive number that is evenly divisible by two numbers you input into the function. (For example, your input is 6 and 9, you need to find the smallest number which can be divided by 6, 7, 8 and 9)

Answer 1

SOURCE CODE:

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**Please look at the Screenshot below and use this code to copy-paste.

***The code in the below screenshot is neatly indented for better understanding.

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# Find the GCD of the numbers x and y.

gcd = function (x, y) ifelse(x == 0, y, gcd(y %% x, x))

# Find the LCM here

lcm = function (x, y) x*y/gcd(x,y)

# Use the reduce function to do the process

# Pass the arguments start:stop to the function

print(Reduce(lcm, 1:10))

print(Reduce(lcm, 1:20))

print(Reduce(lcm, 6:9))

print(Reduce(lcm, 3:7))

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