Question

In: Physics

During a free dance program in figure skating, Victor (m=71 kg) glides at 2.1 m/s to...

During a free dance program in figure skating, Victor (m=71 kg) glides at 2.1 m/s to a stationary Shae-Lynn (52 kg) and hangs on.

a) What is their final speed?

b) How long will the pair slide after the "collision"?

c) How far will the pair slide after the "collision" if coefficient of kinetic friction µk between their skates and the ice is 0.052?

Expert Solution

a) During collision, net external force is zero if we consider both Victor and Lynn as a system.

So, momentum will be conserved.

Initial momentum = Final mometum

71 * 2.1 = (71 + 52) * v

v = 1.212 m/s

b) Since there is no frictioned mentioned in the question till now, I assume the surface is frictionless. So the pair will keep on sliding indefinately.

c) Given, _k = 0.052

Normal reaction force = (m1+m2)g = (52+71) * 9.8 = 1205.4 N

frictional force = _k N = 0.052 * 1205.4 = 62.681 N

acceletration = -f/m = _k g = -0.052 * 9.8 = -0.51m/s²

Using equation of motion , v² = u² + 2aS

v=0, u=1.212 m/s, a=-0.51m/s²

S = 1.44 m (Answer)

genius_generous answered 2 years ago

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