Question

1. Convert the following MIPS instructions into machine code. Directly write down the answer without justifying steps will result 0 credit. All steps must be typed in Word.
   1. add $s0, $s1, $s2
   1. 2. lw $s0, 15($s1)

3. beq $s0, $s1, LABEL   #consider LABEL represents the 16-bit value 0x00FF

Answer 1

Solution :

MIPS to machine code :

a) add $s0, $s1, $s2 :
For add instruction, Initial special bits are : 000000
The register $s1 can be written as : 10001
The register $s2 can be written as : 10010
The register $s0 can be written as : 10000
The OPCODE for ADD is : 00000 100000
Hence the instruction in binary can be written as : 00000010001100101000000000100000
The instruction in hex can be written as : 0x02328020

b) lw $s0, 15($s1) :
The load word instruction has opcode of : 100011
The register $s1 can be written as : 10001
The register $s0 can be written as : 10000
The offset here is 0x15 : 0000000000010101
So the instruction in binary can be written as : 10001110001100000000000000010101
The instruction in hexadecimal can be written as : 0x8E300015

c) beq $s0, $s1, LABEL :
The beq instruction has opcode as : 000100
The register $s0 can be written as : 10000
The register $s1 can be written as : 10001
The 16 bit offset here is : 0000000011111111
The instruction in binary can be written as : 00010010000100010000000011111111
The instruction in hexadecimal can be written as : 0x121100FF

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