Question

1. You are offered with a partial specification of a 4x5 2-D array. The partial specification is shown as follows. (Only the first row and the first column are specified.)

-1   -2   -3   -4   -5

-6

-11

-16

You are required to write a C program to perform two tasks.

1. First, to write a sequence of C codes to generate the values for the unspecified elements in the 4x5 2-D array. The array is called A. The row index is denoted by i, and column index is denoted by j. i, j starts from 0. Namely, for first row, i = 0. For first column, j = 0. The values of the unspecified elements are defined as

A[i][j] = A[i-1][j]*A[i][j-1] for i > 0 and for j > 0.

After all elements in the 4x5 2-D array are fully specified, print out the content of the entire 4x5 2-D array according to the format shown below.

Answer 1

Well i have tried to explain each and everything in the code itself . But if you still dont get anything than ask in comment section please.

CODE :

#include <stdio.h>
#define row 4
#define col 5

int main() {

// as size of row and coloumns are predefined
// here long long is taken as multiplication can overflow
long long int A[row][col];

// putting te known values in A[][]
// initialsed first row first
for(int i=0;i<col;i++){
A[0][i]=-(i+1);   
}
// now first col is initialsed
for(int i=0;i<row;i++){
A[i][0]=-(5*i+1);   
}

// now the main part begins as we have already filled 1st row and 1 st col
// now we will traverse full 2d array starting from 1,1 to 3,4

for(int i=1;i<row;i++){
for(int j=1;j<col;j++){
A[i][j]=A[i-1][j]*A[i][j-1];   
}   
}

// finally printing arrary

for(int i=0;i<row;i++){
for(int j=0;j<col;j++){
printf("%lld ",A[i][j]);
}
printf("\n");
}

return 0;
}

OUTPUT :