Question

Python regex

How to write the regex in Python that only include the contents within a parentheses?

e.g. "uio" [ek3k 0die] 4229834

return "ek3k 0die"

Answer 1

How to write the regex in Python that only include the contents within a parentheses?

e.g. "uio" [ek3k 0die] 4229834

return "ek3k 0die"

code to get the content within the bracket

save the file with .py extension

or execute in python console:

Code

import re #regular expression module imported

a='"uio" [ek3k 0die] 4229834' # declare your string

o=re.search(r"\[((\w*\s*\w*)*)\]",a,re.X) # we will use search function to match the regular o.group(1) # to access search object by group method #expression

**********************************************************

regular expression explanation

it shoud contain open square bracket parentheses and followed by any charater and any number of times and ends with closed square bracket parentheses

* => it indicates 0 or more times occurences

/[ ( (\w* \s* \w*)* ) \]

first open bracket then any character any number of times(denoted by \w* ) any number of spaces (\s*) any number of characters (\w*) and whole * to repeat the pattern.

output:

DONT FORGET TO IMPORT RE