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The active element of a certain laser is an ordinary glass rod 18.1 cm long and 1.16 cm in diameter. If the temperature of the rod increases by 70.3

Answer 1

relation between the coefficient of linear and arieal and volume expansion is

now change in length =9*10^-6*70.3*18.1=11451.87*10^-6 cm,

increase in volume delta v= 3*coeff of linear expansion*change in temperature* volume

                                         =3*0.1145187*70.3*3.14*18.1*1.16=1592.279 cm3

change in diameter = coef of areal expansion*diameter/change in temperature

                               = 2*0.1145187*1.16/70.3

                               =3.779*10^-3 cm