In: Finance
Company B must choose one of two methods for its validation activity. Based on the information below, perform an AW analysis and make recommendation. MARR is 10% per year compounded quarterly. Please use the AW analysis.
| 
 Method  | 
 X  | 
 Y  | 
| 
 Initial Cost  | 
 100,000  | 
 250000  | 
| 
 Annual Operation Cost  | 
 30,000 in year one increasing by 5000 each year  | 
 200,00  | 
| 
 Salvage Value  | 
 0  | 
 0  | 
| 
 Estimated Life in Year  | 
 3  | 
 6  | 
Please see below correct answer. How do you get this? Use Excel.
| X | Y | |
| FV | ||
| PMT | ($75,152.98) | ($78,044.72) | 
| Winner | 
| Method X | |||
| 1.1 | |||
| a | b | a*b | |
| Year | Outflows | PV factor 10% [1/(1+r)^n] | PV | 
| 0 | (100,000.00) | 1.000 | (100,000.00) | 
| 1 | (30,000.00) | 0.909 | (27,272.73) | 
| 2 | (35,000.00) | 0.826 | (28,925.62) | 
| 3 | (40,000.00) | 0.751 | (30,052.59) | 
| Total | 2.487 | (186,250.94) | |
| Total Pv of outflow (a) | (186,250.94) | ||
| Total PV factor for the period (b) | 2.487 | ||
| Equivalent annual cost (a/b) | (74,894.26) | ||
| Method Y | |||
| 1.1 | |||
| a | b | a*b | |
| Year | Outflows | PV factor 10% [1/(1+r)^n] | PV | 
| 0 | (250,000.00) | 1.000 | (250,000.00) | 
| 1 | (20,000.00) | 0.909 | (18,181.82) | 
| 2 | (20,000.00) | 0.826 | (16,528.93) | 
| 3 | (20,000.00) | 0.751 | (15,026.30) | 
| 4 | (20,000.00) | 0.683 | (13,660.27) | 
| 5 | (20,000.00) | 0.621 | (12,418.43) | 
| 6 | (20,000.00) | 0.564 | (11,289.48) | 
| 4.355 | (337,105.21) | ||
| Total Pv of outflow (a) | (337,105.21) | ||
| Total PV factor for the period (b) | 4.355 | ||
| Equivalent annual cost (a/b) | (77,401.85) | ||
| Notes: | |
| 1. In total PV factor 1 should be deducted since 0th year factor will not be taken | |
| 2. Values has small difference since the PV factor digits may vary | |
| Conclusion | 
| Since method X has lowest equivalent annual cost it is the clear winner. |