In: Finance
Company B must choose one of two methods for its validation activity. Based on the information below, perform an AW analysis and make recommendation. MARR is 10% per year compounded quarterly. Please use the AW analysis.
Method |
X |
Y |
Initial Cost |
100,000 |
250000 |
Annual Operation Cost |
30,000 in year one increasing by 5000 each year |
200,00 |
Salvage Value |
0 |
0 |
Estimated Life in Year |
3 |
6 |
Please see below correct answer. How do you get this? Use Excel.
X | Y | |
FV | ||
PMT | ($75,152.98) | ($78,044.72) |
Winner |
Method X | |||
1.1 | |||
a | b | a*b | |
Year | Outflows | PV factor 10% [1/(1+r)^n] | PV |
0 | (100,000.00) | 1.000 | (100,000.00) |
1 | (30,000.00) | 0.909 | (27,272.73) |
2 | (35,000.00) | 0.826 | (28,925.62) |
3 | (40,000.00) | 0.751 | (30,052.59) |
Total | 2.487 | (186,250.94) | |
Total Pv of outflow (a) | (186,250.94) | ||
Total PV factor for the period (b) | 2.487 | ||
Equivalent annual cost (a/b) | (74,894.26) |
Method Y | |||
1.1 | |||
a | b | a*b | |
Year | Outflows | PV factor 10% [1/(1+r)^n] | PV |
0 | (250,000.00) | 1.000 | (250,000.00) |
1 | (20,000.00) | 0.909 | (18,181.82) |
2 | (20,000.00) | 0.826 | (16,528.93) |
3 | (20,000.00) | 0.751 | (15,026.30) |
4 | (20,000.00) | 0.683 | (13,660.27) |
5 | (20,000.00) | 0.621 | (12,418.43) |
6 | (20,000.00) | 0.564 | (11,289.48) |
4.355 | (337,105.21) | ||
Total Pv of outflow (a) | (337,105.21) | ||
Total PV factor for the period (b) | 4.355 | ||
Equivalent annual cost (a/b) | (77,401.85) |
Notes: | |
1. In total PV factor 1 should be deducted since 0th year factor will not be taken | |
2. Values has small difference since the PV factor digits may vary |
Conclusion |
Since method X has lowest equivalent annual cost it is the clear winner. |