In: Physics
A certain brand of freezer is advertised to use 685 kW · h of energy per year. (a) Assuming the freezer operates for 4.5 hours each day, how much power does it require while operating? W (b) If the freezer keeps its interior at a temperature of −9.5°C in a 21.4°C room, what is its theoretical maximum performance coefficient? (c) What is the theoretical maximum amount of ice this freezer could make in an hour, starting with water at 21.4°C?
Hello let's solve this problem:
For A
we have that
This is the W spent each hour it functions. Meaning that each day it will spend:
ANSWER FOR B (you can just put 351.9 W in 4.5 hours)
Now for B
The greatest performance coefficient is that of a Carnot's machine. And the formula to determine this for cooling machines is:
Before solving to find the coefficient all temperatures must be converted into K
K=oC+273.15
Then we have that:
ANSWER FOR B
For C
Let's recall that the specific heat and the latent heat for water is:
Cw is the same value for Kelvin degrees.
We have two different phases.
First we have to change the temperature of water to 0 C this Q1.
Then we have to convert this unknown mass of water into ice, this is Q2.
But there is a total heat used in both fases:
We can find this total Q:
We spend 78.2 W an hour, and an hour has 3600 seconds:
Now to find the mass of water converted into ice we return to
Remember
Then
We now simply clear Mw:
We proceed to find delta T which will have a negative sign, because the temperature is diminishing.
The temperature of water in Kelvin is 295.55
We now have all the data and after making the substitution in:
We will find that:
Good luck