In: Statistics and Probability
PREGUNTA 14
Use the following information to answer questions 14 to 18.
to A certain brand of apple juice is supposed to have 64 ounces of juice. Because the punishment for under-filling bottles is severe, the target mean amount of juice is 64.05 ounces. It is known that the standard deviation of the population is 0.06. However, the filling machine is not precise, and the exact amount of juice varies from bottle to bottle. The quality – control manager wishes to verify that the amount of juice in each bottle is 64.05 ounces so that she can be sure that the machine is not over – or under-filling. She randomly samples 22 bottles of juice and measures the content and obtains that xavg = 64.007. (Use α = 0.01)
The null and alternative hypothesis are:
A. |
None of the above |
|
B. |
H0: u = 64.05 versus H1: u ≠ 64.05 |
|
C. |
H0: u = 64.05 versus H1: u > 64.05 |
|
D. |
H0: u = 64.05 versus H1: u < 64.05 |
5 puntos
PREGUNTA 15
The test statistic is equal to:
A. |
z = 3.36 |
|
B. |
t = 3.36 |
|
C. |
z= - 3.36 |
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D. |
t = - 3.36 |
5 puntos
PREGUNTA 16
The critical value is:
A. |
z ± 2.58 |
|
B. |
t ± 2.33 |
|
C. |
t ± 2.58 |
|
D. |
z ± 2.33 |
5 puntos
PREGUNTA 17
The p-value is approximately:
A. |
pvalue = 0.0049 |
|
B. |
pvalue = 0 |
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C. |
pvalue = 1 |
|
D. |
pvalue = 0.01 |
5 puntos
PREGUNTA 18
The conclusion is to Reject the Null Hypothesis
Verdadero
Falso
given data are:-
sample mean () = 64.007
population sd () = 0.06
sample size (n) = 22
14).hypothesis:-
15).the test statistic is:-
16).the critical value be:-
[ for 99% confidence level]
17). p value be:-
[ from standard normal table]
18).conclusion:-
p value = 0 < 0.01 (alpha)
so, we reject the null hypothesis.
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