Question

In: Physics

To find the height of an overhead power line, you throw a ball straight upward. The...

To find the height of an overhead power line, you throw a ball straight upward. The ball passes the line on the way up after 0.85 s , and passes it again on the way down 1.5 s after it was tossed.

a) What is the height of the power line?

b) What is the initial speed of the ball?

Expert Solution

Given that the ball passes the power line at 0.85s and 1.5s after it was tossed.

That means the ball reached its max height in the middle of that time period.

Time Period = 1.5s - 0.85s = 0.65s

Middle of the time period = 0.65s/2 =0.325s

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The ball reached its max height at ( 0.85s + 0.325s) 1.175s after it was tossed

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Consider the ball going up

Use formula

At max height velocity becomes zero.

The ball is going up and g is acting downwards ,so put negative sign.

b)ANSWER :

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(a) Given that the ball passes the power line at 0.85s while going up

Use formula

The ball is going up and g is acting downwards ,so put negative sign.

(a) ANSWER :

============================

genius_generous answered 10 months ago

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