Python Implement function noVowel() that takes a string s as input and returns True if no...

Python

Implement function noVowel() that takes a string s as input and returns True if no char- acter in s is a vowel, and False otherwise (i.e., some character in s is a vowel).

>>> noVowel('crypt')

True

>>> noVowel('cwm')

True

>>> noVowel('car')

False

Expert Solution

Your function source code is like below:-

def noVowel(str):
   flag=0
   for letter in str:
       if letter=='a' or letter=='e' or letter=='i' or letter=='o' or letter=='u' :
           flag=1
           break
   if flag==1:
       return False
   else:
       return True

For testing purpose, you can use below code and save that in the file ("Saved file name with str.py") and run according to the below screenshot:

def noVowel(str):
   flag=0
   for letter in str:
       if letter=='a' or letter=='e' or letter=='i' or letter=='o' or letter=='u' :
           flag=1
           break
   if flag==1:
       return False
   else:
       return True

name = input('Enter a word:')
print (noVowel(name))

Hope so this will solve your problem.

venereology answered 2 hours ago

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