Question

In: Chemistry

You add 0.535 g of NaOH to 100.0 mL of water at 25

Expert Solution

Molar mass of NaOH = atomic mass of Na + atomic mass of O + atomic mass of H

= 23 + 16 + 1

= 40 gmol ^-1

Given mass of NaOH , M = 0.535 g

So no.of moles ,

Molarity of the solution ,

M = 0.134 M

NaOH Na⁺ + OH ^-

1 mole of NaOH produces 1 mole of OH^-

So concentration of [OH^-] = concentration of NaOH

= 0.134 M

pOH = - log[OH^-]

= - log 0.134

= 0.87

pH = 14-pOH

= 14-0.87

= 13.13

pH = -log[H₃O⁺]

[H₃O⁺]= 10^-pH

= 10 ^-13.13

= 7.4810^-14 M

queen_honey_blossom answered 3 weeks ago

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