In: Statistics and Probability
1. Assume that a sample is used to estimate a population
proportion p. Find the margin of error M.E. that corresponds to a
sample of size 224 with 25 successes at a confidence level of
99.8%.
M.E. = ___%
2. Assume that a sample is used to estimate a population
proportion p. Find the margin of error M.E. that
corresponds to a sample of size 310 with 46.1% successes at a
confidence level of 99.5%.
M.E. = ____%
3.Assume that a sample is used to estimate a population
proportion p. Find the 98% confidence interval for a
sample of size 251 with 161 successes. Enter your answer as an
open-interval (i.e., parentheses) using
decimals (not percents) accurate to three decimal places.
98% C.I. = ____
(1) proportion p = (success)/(total sample size) = 25/224 = 0.1116
sample size n = 224
Significance level = 1-(99.8/100) = 1-0.998 = 0.002
using z distribution table for 0.002 significance level, we get z critical value = 3.09
Formula for margin of error is given as
setting the values, we get
converting to %, we get 0.065*100 = 6.5%
Therefore, required margin of error is 6.5% (rounded to 1 decimal) or 6.50% (rounded to 2 decimal)
(2) proportion p = 46.1/100 = 0.461
sample size n = 310
Significance level = 1-(99.5/100) = 1-0.995 = 0.005
using z distribution table for 0.005 significance level, we get z critical value = 2.81
Formula for margin of error is given as
setting the values, we get
converting to %, we get 0.0796*100 = 7.96 or 8.0 %
Therefore, required margin of error is 8.0% (rounded to 1 decimal) or 7.96% (rounded to 2 decimal)
(3) it is given that there are 161 successes out of 251
So, proportion = 161/251
significance level = 1-(confidence level)/100 = 1-(98/100) = 0.02
Using z distribution table for 0.02 level of significance, we get z critical value = 2.33
sample size is n= 251
Using the formula for the confidence interval, we can write
setting the given values, we get
this gives us
or, we can write it as
So, we get Confidence interval = (0.571,0.712)
Therefore, required 98% confidence interval is (0.571,0.712) (rounded to 3 decimals)