2. Determine if the following series converge or diverge.
Justify your answers, citing any appropriate tests for convergence
that you use.
(a) sigma^infinity_n=1 n + 2/(n^5/3 + n + 5 )
(b) sigma^infinity_n=1 (1 − 1/ n)^n ^2
Determine if the following series converge or diverge. If it
converges, find the sum.
a. ∑n=(3^n+1)/(2n) (upper limit of sigma∞, lower limit is
n=0)
b.∑n=(cosnπ)/(2) (upper limit of sigma∞ , lower limit is n=
1
c.∑n=(40n)/(2n−1)^2(2n+1)^2 (upper limit of sigma ∞ lower limit
is n= 1
d.)∑n = 2/(10)^n (upper limit of sigma ∞ , lower limit of sigma
n= 10)
PLEASE can u demonstrate the binomial
tree model for this question! And tell me how to work out the
payoffs for the 2 period put!!
Thanks
Q- The current price of Excel Network Systems stock is £60 per
share. In each of the next two years the stock price will either
increase by 20% or decrease by 10%. The 3% one year risk free rate
of interest will remain constant. Calculate the price of a two year
European put option...
can u pls tell me how much it will cost to make 1 g of
C2H5Br by using this reaction : ethane + Br2
& heat = CH3CH2BR
we have 398 grams of ethane and it costs 226.32 dollars
we have 684 grams of bromine and it costs 65.82 dollars
u can presume that we have a perfiect yeild and pls round the
answer to the nearest cent
show all work pls ty
1. Given the series:
∞∑k=1 2/k(k+2)
does this series converge or diverge?
converges
diverges
If the series converges, find the sum of the series:
∞∑k=1 2/k(k+2)=
2. Given the series:
1+1/4+1/16+1/64+⋯
does this series converge or diverge?
diverges
converges
If the series converges, find the sum of the series:
1+1/4+1/16+1/64+⋯=
When does a series converge?
Does the harmonic series converge?
Can you find another series which seems like it should
converge
, but it diverges?
Does the alternating harmonic series converge?
Check all of the following that are true for the series
∑n=1∞(n−8)cos(nπ)/(n^2).
Converge, diverge, integral test, comparison test, limit
comparison, ratio test, and alternation test.
Same with ∑n=1∞8^n/((4^n)-1)