In: Math
A fun size bag of M&Ms has 4 blue, 3 orange, 3 red, 2 green, 2 yellow, and 1 brown M&Ms. What is the probability of randomly selecting 5 M&Ms where 3 are blue and 2 are orange?
Number of blue M&Ms in a fun size bag = 4
Number of orange M&Ms in a fun size bag = 3
Number of red M&Ms in a fun size bag = 3
Number of green M&Ms in a fun size bag = 2
Number of yellow M&Ms in a fun size bag = 2
Number of brown M&Ms in a fun size bag = 1
Total number of M&Ms in a fun size bag = 4+3+3+2+2+1=15
Probability of randomly selecting 5 M&Ms where 3 are blue and 2 are orange
= (Number of ways of selecting 3 blue M&Ms from 4 blue M&Ms x Number of ways of selecting 2 orange M&Ms from 3) / Number of ways of selecting 5 M&Ms from a total of 15 M&Ms
Number of ways of selecting 3 blue M&Ms from 4 blue M&Ms = =4
Number of ways of selecting 2 orange M&Ms from 3 = =3
Number of ways of selecting 5 M&Ms from a total of 15 M&Ms==3003
Probability of randomly selecting 5 M&Ms where 3 are blue and 2 are orange
= (Number of ways of selecting 3 blue M&Ms from 4 blue M&Ms x Number of ways of selecting 2 orange M&Ms from 3) / Number of ways of selecting 5 M&Ms from a total of 15 M&Ms
= (4 x 3)/3003 = 12/3003 = 0.003996004
Probability of randomly selecting 5 M&Ms where 3 are blue and 2 are orange = 0.003996004