If P=0.4% and n =600. Is the poison distribution a reasonable
approximation distribution of the binomial distribution?
Yes or No
What is the mean of this binomial distribution ( and the mean of
poison distribution used to approximate it)
Mean=
What is the actual mean of this binomial distribution
Standard deviation (actual)=
What is the mean of the approximate poison distribution?
Standard deviation approximate
Are these values in reasonable agreement
Find the mean, variance, and standard deviation of the binomial distribution with the given values of n and p. n=80, p=0.4 The mean, μ, is _______ (Round to the nearest tenth as needed.) The variance, σ2, is _______ (Round to the nearest tenth as needed.) The standard deviation, σ, is _______ (Round to the nearest tenth as needed.)
A binomial probability distribution has p = 0.25 and n = 81.
A) What are the mean and standard deviation?
B) Is this situation one in which binomial probabilities can be
approximated by the normal probability distribution? Explain.
C) What is the probability of exactly 28 successes?
D) What is the probability of 18 to 22 successes?
E)What is the probability of 24 or fewer successes?
Assume a binomial probability distribution has p = 0.70 and n = 300. (a) What are the mean and standard deviation? (Round your answers to two decimal places.) mean Incorrect: Your answer is incorrect. standard deviation Incorrect: Your answer is incorrect. (b) Is this situation one in which binomial probabilities can be approximated by the normal probability distribution? Explain. Yes, because np ≥ 5 and n(1 − p) ≥ 5. Yes, because n ≥ 30. No, because np < 5...
Assume a binomial probability distribution has
p = 0.70
and
n = 400.
(a)
What are the mean and standard deviation? (Round your answers to two decimal places.)
mean=
standard deviation =
(b)
Is this situation one in which binomial probabilities can be approximated by the normal probability distribution? Explain.
Yes, because np ≥ 5 and n(1 − p) ≥ 5.
Yes, because n ≥ 30.
Yes, because np < 5 and n(1 − p) < 5.
No, because...
For a binomial probability distribution, n = 130 and p = 0.60.
Let x be the number of successes in 130 trials. a. Find the mean
and standard deviation of this binomial distribution.
a. Find the mean and the standard deviation of this binomial
distribution.
b. Find to 4 decimal places P(x ≤ 75) using the normal
approximation. P(x ≤ 75) =
c. Find to 4 decimal places P(67 ≤ x ≤ 72) using the normal
approximation. P(67 ≤ x...
In a binomial distribution n = 10 and p =
0.30. Find the probabilities of the following events:
(Round the final answers to 3 decimal places.)
a. x = 2.
Probability
b. x ≤ 2 (the probability that
x is equal to or less than 2).
Probability
c. x ≥ 3 (the probability that
x is equal to or greater than 3).
Probability
Assume a binomial probability distribution has
p = 0.60
and
n = 300.
(a)
What are the mean and standard deviation? (Round your answers to
two decimal places.)
mean standard deviation
(b)
Is this situation one in which binomial probabilities can be
approximated by the normal probability distribution? Explain.
No, because np ≥ 5 and n(1 − p) ≥ 5.
Yes, because n ≥ 30. Yes, because
np ≥ 5 and n(1 − p) ≥ 5. No, because
np <...
Suppose that X is a single observation from a Binomial(n, p)
distribution where n is known and 0 < p < 1 is unknown.
Consider three estimators of p:
pˆ = X /n “sample proportion”
pˆA = (X + 2)/ (n + 4) “plus four estimator”
pˆB = (X + (√n/4))/( n + √ n ). “constant MSE estimator”
(a) Find the bias functions for all three estimators.
(b) Find the variance functions of all three estimators.
(c) Find the...