Question

In: Statistics and Probability

Teacher Data Using the table of random numbers, select 10 states and find the mean of...

Teacher Data Using the table of random numbers, select 10 states and find the mean of the average teacher's pay and the mean of the pupils per teacher. How do your results compare with the U.S. figures?

of U.S. Public Schools

State Pupils per Teacher Teacher's Avg. Pay
AL 16.0 $47,571
AK 14.9 59,672
AZ 18.9 46,952
AR 12.7 14,700
CA 21.4 68,203
CO 17.0 49,202
CT 13.2 64,350
DE 14.4 57,080
FL 15.9 46,708
GA 14.4 53,112
HI 15.2 55,063
ID 18.2 46,283
IL 14.9 62,077
IN 16.7 49,986
IA 13.8 49,626
KS 13.7 46,657
KY 15.8 49,543
LA 14.0 48,903
ME 11.1 46,106
MD 14.3 63,971
MA 13.6 69,273
MI 17.1 57,958
MN 15.4 52,431
MS 31.9 45,644
MO 13.3 45,317
MT 13.4 45,759
NE 13.4 46,227
NV 18.5 51,524
NH 12.7 51,443
NJ 12.0 65,130
NM 14.9 46,258
NY 11.8 71,633
NC 14.8 46,850
ND 12.1 42,964
OH 17.1 55,958
OK 15.5 47,691
OR 18.7 55,224
PA 14.0 59,156
RI 13.0 59,686
SC 14.8 47,508
SD 13.4 38,837
TN 14.7 46,290
TX 14.5 48,261
UT 22.4 45,885
VT 9.8 49,084
VA 11.7 50,015
WA 19.3 53,003
WV 14.3 45,959
WI 14.8 51,264
WY 12.3 55,861
U.S. 15.3 55,202

Solutions

Expert Solution

The mean of the average teacher's pay and the mean of the pupils per teacher for the first ten data sets are calculated

Mean of average Teacher's pay = (sum of all teacher's avg pay for first 10)/(number of number of teacher's avg pay)

this gives

Mean of average teacher's pay =(47571+59672+46952+14700+68203+49202+64350+57080+46708+53112)/10=507550/10

this gives us the Mean of average teacher's pay = $50755

Similarly, mean of pupils per teacher = (sum of pupils per teacher for first 10)/(number of pupils per teacher)

setting the data

we get

mean of pupils per teacher = (16+14.9+18.9+12.7+21.4+17+13.2+14.4+15.9+14.4)/10 = 158.8/10

on solving, we get

mean of pupils per teacher = 15.88

It can be seen that these means for average teacher's pay and number of pupils per teacher are very similar to the US records because there is not much difference the means calculated and given US records.


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