In: Math
SS 
df 
MS 
F 

Rating 
455 

Season 
192.5 

Interaction 
140 
Required Formulae:
DF_{rating} = number of ratings  1
DF_{season} = number of season  1
DF_{interaction} = DF_{rating} * DF_{season}
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SS  df  MS  F  Fcritical  
Rating  455  5  1 = 4  
Season  192.5  2  1 = 1  
Interaction  140  4 * 1 = 4  
Error  1050  69  4  1  4 = 60  
Total  1837.5  70  1 = 69 
a) ANOVA table:
SS  df  MS  F  
Rating  455  4  113.75  6.5 
Season  192.5  1  192.5  11 
Interaction  140  4  35  2 
Error  1050  60  17.5  
Interaction  1837.5  69 
b) critical value:
Critical value for rating is 2.525.
Critical value for Season is 4.001
Critical value for interaction is 2.525
c)
i) Rating:
6.5 > 2.525
Therefore, we reject null hypothesis.
There is sufficient evidence to conclude that box office revenue vary with ratings of the movie.
ii) Season:
11 > 4.001
Therefore, we reject null hypothesis.
There is sufficient evidence to conclude that box office revenue vary with season in which movie releases.
iii) Interaction:
2 < 2.525
Therefore, we fail to reject null hypothesis.
There is sufficient evidence to conclude that box office revenue does not vary with interaction of season and movie rating.