In: Operations Management
Twenty samples of n = 200 were taken by an operator at a
workstation in a production
process. The number of defective items in each sample were recorded
as follows
Sample | number of defectives | Sample | number of defectives | ||
1 | 12 | 11 | 16 | ||
2 | 18 | 12 | 14 | ||
3 | 10 | 13 | 12 | ||
4 | 14 | 14 | 16 | ||
5 | 16 | 15 | 18 | ||
6 | 19 | 16 | 20 | ||
7 | 17 | 17 | 18 | ||
8 | 12 | 18 | 20 | ||
9 | 11 | 19 | 21 | ||
10 | 14 | 20 | 22 | ||
1- develop a P-chart using 3-sigma , set p the P chart and plot the observations to determine if the process was out of control at any point.
2- if the management want to use the pattern tests using 1-sigma , 2- sigma and 3-sigma to further determine if the process is in control . Determine the " up-and-down" and " above -and -below" runs and zone observations to make your recommendation using the control chart.
Ans. 1)
Sample | No. of Defective (di) | P = (No. of defect/ Sample size) |
1 | 12 | 0.06 |
2 | 18 | 0.09 |
3 | 10 | 0.05 |
4 | 14 | 0.07 |
5 | 16 | 0.08 |
6 | 19 | 0.095 |
7 | 17 | 0.085 |
8 | 12 | 0.06 |
9 | 11 | 0.055 |
10 | 14 | 0.07 |
11 | 16 | 0.08 |
12 | 14 | 0.07 |
13 | 12 | 0.06 |
14 | 16 | 0.08 |
15 | 18 | 0.09 |
16 | 20 | 0.1 |
17 | 18 | 0.09 |
18 | 20 | 0.1 |
19 | 21 | 0.105 |
20 | 22 | 0.11 |
Ans 2)
P value of all samples are within control limit.
Rule 2 - Zone A - For sample 2 and 3, there is sudden change in the p value. It is a special cause or one time occurence event.
Rule 3 - Zone B - From sample 4-7, there is a one directional shift with small changes
Rule 4 - Zone C - From sample 14-20 there is a long one directional shift with small changes.
Possible cause of error for Zone A might be because of wrong setup or new person doing the job. It can be prevent by havindg robust standard operating procedure.
Possible cause of error for Zone C might be because of change in Raw Material or Change in Setup procedure. It can be prevent by adjust the process in line with the other changes.