In: Statistics and Probability
| 
 Airline  | 
 United  | 
 Southwest  | 
| 
 Sample Size  | 
 40  | 
 42  | 
| 
 Average Number of Delays per Month  | 
 141  | 
 361  | 
| 
 Population Standard Deviation  | 
 270  | 
 402  | 
(A) Population standard deviations are known and sample sizes are big enough, so we will use z distribution
formula for the confidence interval of mean difference is given as

setting the values from the question 
 and z score for 98% confidence interval is 2.33 (using
distribution critical value table)
we get

this gives us

So, 98% confidence interval for the mean difference is (-395.451,-44.549)
(B) Since population standard deviations are known and sample sizes are big enough, so we will use z distribution. So, a two-Sample z-test for Comparing two means is best suited for testing the hypothesis
Formula for z test statistic is given as

setting the given values, we get

on solving, we get
z =-220/75.30 = -2.92
So, required test statistic is z= -2.92