Parallel-plates in a capacitor, with area 1.2×10−3 cm2 and air-filled separation of 10 mm, are charged...

Parallel-plates in a capacitor, with area 1.2×10⁻³ cm² and air-filled separation of 10 mm, are charged by a 12 V battery. They are disconnected from the battery and pushed together (with no discharge) to a separation of 3.5 mm.

a) Find the initial and final potential difference between the plates and the initial and final stored energy

b) How much work is required to decrease the separation between the plates and where does this work come from?

c) After the decrease in separation, a dielectric with constant K = 4.5 is added. Find the new potential difference between the plates and the new stored energy.

d) How much work is required to add the dielectric between the plates and where does the work come from?

Expert Solution

genius_generous answered 2 years ago

The parallel-plates in a capacitor, with a plate area 1.2×10−3 cm2 and an air-filled separation of...

The parallel-plates in a capacitor, with a plate area 1.2×10−3 cm2 and an air-filled separation of 10 mm, are charged by a 12 V battery. They are then disconnected from the battery and pushed together (without discharge) to a separation of 3.5 mm. (a) Find the initial potential difference between the plates and the initial stored energy. (6 points) (b) Find the final potential difference between the plates and the final stored energy. (6 points) (c) How much work is...

The plates of an air-filled parallel-plate capacitor with a plate area of 15.0 cm2 and a...

The plates of an air-filled parallel-plate capacitor with a plate area of 15.0 cm2 and a separation of 8.95 mm are charged to a 170-V potential difference. After the plates are disconnected from the source, a porcelain dielectric with κ = 6.5 is inserted between the plates of the capacitor. (a) What is the charge on the capacitor before and after the dielectric is inserted? Qi = C Qf = C (b) What is the capacitance of the capacitor after...

An air-filled capacitor consists of two parallel plates, each with an area of 7.60 cm2

An air-filled capacitor consists of two parallel plates, each with an area of 7.60 cm2, separated by a distance of 2.20 mm. A 23.0-V potential difference is applied to these plates. (a) Calculate the electric field between the plates. kV/m (b) Calculate the surface charge density. nc/m2 (c) Calculate the capacitance. pF (d) Calculate the charge on each plate. pC

A parallel plate, air filled capacitor, has plates of area 0.82 m2 and a separation of...

A parallel plate, air filled capacitor, has plates of area 0.82 m2 and a separation of 0.040 mm. (a) Find the capacitance. (b) If a voltage of 25 volts is applied to the capacitor, what is the magnitude of the charge on each plate? (c) What is the energy stored in the capacitor? Now the plates are filled with strontium titanate having a dielectric constant of 310 and a dielectric strength of 8.0 kV/mm. (d) What is the new value...

An air-filled capacitor consists of two parallel plates, each with an area of 7.60 cm2, separated...

An air-filled capacitor consists of two parallel plates, each with an area of 7.60 cm2, separated by a distance of 2.00 mm. (a) If a 16.0 V potential difference is applied to these plates, calculate the electric field between the plates. kv/m (b) What is the surface charge density? nC/m2 (c) What is the capacitance? pF (d) Find the charge on each plate. pC

An air-filled parallel-plate capacitor has plates of area 2.50 cm separated by 1.00 mm. The capacitor...

An air-filled parallel-plate capacitor has plates of area 2.50 cm2 separated by 1.00 mm. The capacitor is connected to a 24.0-V battery. (a) Find the value of its capacitance._______ pF (b) What is the charge on the capacitor? _______ pC (c) What is the magnitude of the uniform electric field between the plates? _______ V/m

A dielectric-filled capacitor consists of two parallel plates, each with an area A = 15.0 cm2 ,...

A dielectric-filled capacitor consists of two parallel plates, each with an area A = 15.0 cm2 , seperated by a distance of d = 10.0 mm and dielectric constant k = 4.00. A potential difference V= 10.0 V is applied to these plates . Throughout the problem, use ϵ0 = 8.85×10−12 C2/N⋅m2 Part A) Calculate the energy U1of the dielectric-filled capacitor.(J) Part B) The capacitor remains connected to the battery. Calculate the energy U2 of the capacitor at the moment when the capacitor...

An air-filled parallel-plate capacitor has plates of area 2.40 cm^2 separated by 3.00 mm. The capacitor...

An air-filled parallel-plate capacitor has plates of area 2.40 cm^2 separated by 3.00 mm. The capacitor is connected to a(n) 23.0 V battery. (a) Find the value of its capacitance. pF (b) What is the charge on the capacitor? pC (c) What is the magnitude of the uniform electric field between the plates? N/C

A parallel-plate capacitor has an area of 5.00 cm2, and the plates are separated by 2.00 mm with...

A parallel-plate capacitor has an area of 5.00 cm2, and the plates are separated by 2.00 mm with air between them. The capacitor stores a charge of 500 pC.(a) What is the potential difference across the plates of the capacitor?1 V(b) What is the magnitude of the uniform electric field in the region between the plates?

A parallel-plate capacitor has 2.18 cm2 plates that are separated by 5.69 mm with air between...

A parallel-plate capacitor has 2.18 cm2 plates that are separated by 5.69 mm with air between them. If a 18.0 V battery is connected to this capacitor, how much energy does it store?

Question