In: Economics
Based on your analysis, which depreciation method is most profitable for the firm?
(a) Straight-line (SLM) method
SL annual depreciation = Cost / Useful life = 200,000 / 10 = 20,000
SLM depreciation schedule as follows.
SLM | ||||
Year | Beginning-of-year Book Value ($) | Annual Depreciation ($) | Accumulated Depreciation ($) | End-of-Year Book Value ($) |
1 | 2,00,000 | 20,000 | 20,000 | 1,80,000 |
2 | 1,80,000 | 20,000 | 40,000 | 1,60,000 |
3 | 1,60,000 | 20,000 | 60,000 | 1,40,000 |
4 | 1,40,000 | 20,000 | 80,000 | 1,20,000 |
5 | 1,20,000 | 20,000 | 1,00,000 | 1,00,000 |
6 | 1,00,000 | 20,000 | 1,20,000 | 80,000 |
7 | 80,000 | 20,000 | 1,40,000 | 60,000 |
8 | 60,000 | 20,000 | 1,60,000 | 40,000 |
9 | 40,000 | 20,000 | 1,80,000 | 20,000 |
10 | 20,000 | 20,000 | 2,00,000 | 0 |
TOTAL | 2,00,000 |
(b) DDB method
Straight line depreciation rate = 1 / Useful life = 1/10 = 0.1
DDB depreciation rate = 2 x SLM rate = 2 x 0.1 = 0.2
Depreciation schedule as follows.
DDB | |||||
Year | Beginning-of-year Book Value ($) | Depreciation Rate | Annual Depreciation ($) | Accumulated Depreciation ($) | End-of-Year Book Value ($) |
1 | 2,00,000 | 0.20 | 40,000 | 40,000 | 1,60,000 |
2 | 1,60,000 | 0.20 | 32,000 | 72,000 | 1,28,000 |
3 | 1,28,000 | 0.20 | 25,600 | 97,600 | 1,02,400 |
4 | 1,02,400 | 0.20 | 20,480 | 1,18,080 | 81,920 |
5 | 81,920 | 0.20 | 16,384 | 1,34,464 | 65,536 |
6 | 65,536 | 0.20 | 13,107 | 1,47,571 | 52,429 |
7 | 52,429 | 0.20 | 10,486 | 1,58,057 | 41,943 |
8 | 41,943 | 0.20 | 8,389 | 1,66,446 | 33,554 |
9 | 33,554 | 0.20 | 6,711 | 1,73,156 | 26,844 |
10 | 26,844 | 0.20 | 5,369 | 1,78,525 | 21,475 |
TOTAL | 1,78,525 |
(c) SOYD method
Sum-of-years-digit (SOYD) = 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 = 55
Annual depreciation in year N = Cost x (Number of years remaining at beginning of year N / SOYD)
= 200,000 x (Number of years remaining at beginning of year N / 55)
Depreciation schedule as follows.
SOYD | |||||
Year | Net Cost ($) | Depreciation Rate | Annual Depreciation ($) | Accumulated Depreciation ($) | End-of-Year Book Value ($) |
1 | 2,00,000 | 10/55 | 36,364 | 36,364 | 1,63,636 |
2 | 2,00,000 | 9/55 | 32,727 | 69,091 | 1,30,909 |
3 | 2,00,000 | 8/55 | 29,091 | 98,182 | 1,01,818 |
4 | 2,00,000 | 7/55 | 25,455 | 1,23,636 | 76,364 |
5 | 2,00,000 | 6/55 | 21,818 | 1,45,455 | 54,545 |
6 | 2,00,000 | 5/55 | 18,182 | 1,63,636 | 36,364 |
7 | 2,00,000 | 4/55 | 14,545 | 1,78,182 | 21,818 |
8 | 2,00,000 | 3/55 | 10,909 | 1,89,091 | 10,909 |
9 | 2,00,000 | 2/55 | 7,273 | 1,96,364 | 3,636 |
10 | 2,00,000 | 1/55 | 3,636 | 2,00,000 | 0 |
TOTAL | 2,00,000 |
(d)
The lower the total depreciation over project life, the higher the net profit of the project over its lifetime. Since DDB method has lowest total depreciation over project life, this method leads to highest profitability.