In: Math
1. The distribution of diastolic blood pressures for
the population of female diabetics between the ages of 30 and 34
has an unknown mean and standard deviation. A sample of 10
diabetic women is selected; their mean diastolic blood pressure is
84 mm Hg. We want to determine whether the diastolic blood pressure
of female diabetics are different from the general population of
females in this age group, where the mean μ = 74.4 mmHg and
standard deviation σ = 9.1 mm Hg. Diastolic blood pressure is
normally distributed.
a) Create a two-sided 95% confidence interval to determine whether
diabetic women have a different mean diastolic blood pressure
compared to the general population.
b) Now, conduct a two-sided hypothesis test at the α = 0.05 level
of significance to determine whether diabetic women have a
different mean diastolic blood pressure compared to the general
population. Use both critical value and p-value
methods.
For either method, would your conclusion have been different if you
had chosen α = 0.01 instead of α = 0.05?
a) At 95% confidence interval the critical value is z0.025 = 1.96
The 95% confidence interval is
+/- z0.025 *
= 84 +/- 1.96 * 9.1/
= 84 +/- 5.64
= 78.36, 89.64
b) H0: = 74.4
H1: 74.4
The test statistic z = ()/()
= (84 - 74.4)/( 9.1/)
= 3.34
At = 0.05, the critical value is +/- z0.025 = 1.96
Since the test statistic value is greater than the positive critical value (3.34 > 1.96), so we should reject the null hypothesis.
P-value = 2 * P(Z > 3.34)
= 2 * (1 - P(Z < 3.34))
= 2 * (1 - 0.9996)
= 0.0008
Since the P-value is less than the significance level(0.0008 < 0.05), so we should reject the null hypothesis.
At 0.05 significance level, there is sufficient to conclude that the diastolic blood pressure of female diabetics are different from the general population of females in this age group.
At = 0.01, since the P-value is less than , so we should reject the null hypothesis.
No, the conclusion would not have been different if we had chosen = 0.01 instead of = 0.05.