In: Statistics and Probability
Jason Lowrey is a frequent traveler between Los Angeles and San Francisco. For the past month, he wrote down the flight times for three different airlines. The results are contained in the attached file: Flight Times Spring 2019.
Use the .05 significance level and the six-step hypothesis-testing process to check if there is a difference in the mean flight times among the three airlines. Write a statement to Mr. Lowrey explaining your results. Do your work in Excel
| Western Air | NW Skyway | Skyliner |
| 52 | 51 | 50 |
| 55 | 46 | 53 |
| 60 | 52 | 48 |
| 58 | 48 | 62 |
| 52 | 51 | 53 |
| 49 | 55 | 49 |
| 49 | 47 | 50 |
| 51 | 47 | 49 |
| 50 | 54 | |
| 60 | 54 | |
| 51 | 51 | |
| 49 | 49 | |
| 49 | ||
| 50 |
Go to excel data analysis tab -> select one way ANOVA->select data click ok...
Following is the output of ANOVA:

Hypotheses are:
H0: There is no difference in the mean flight times among the three airlines.
Ha: There is a difference in the mean flight times among the three airlines.
The level of significance is 0.05
The critical value is 3.305
The F test statistics is
F = 1.172
Since F < 3.305 so we fail to reject the null hypothesis.
The p-value is 0.3231
Since p-value is greater than 0.05 so we fail to reject the null hypothesis.
Conclusion: We cannot conclude that there is a difference in the mean flight times among the three airlines.