Question

8. A random sample of 10 subjects have weights with a standard deviation of

12.4989

kg. What is the variance of their​ weights? Be sure to include the appropriate units with the result.

The variance of the sample data is

nothing

▼

.kg2.

kg.

kg3.

​(Round to four decimal places as​ needed.)

9. Below are the jersey numbers of 11 players randomly selected from a football team. Find the​ range, variance, and standard deviation for the given sample data. What do the results tell​ us?

97 40 66 3 52 50 91 73 84 85 2

Range equals=nothing

​(Round to one decimal place as​ needed.)

Sample standard

Deviation equals=nothing

​(Round to one decimal place as​ needed.)

Sample

Variance equals=nothing

​(Round to one decimal place as​ needed.)

12. A successful basketball player has a height of 6 feet

22

​inches, or

188

cm. Based on statistics from a data​ set, his height converts to the z score of

1.95

How many standard deviations is his height above the​ mean?

The​ player's height is

nothing

standard​ deviation(s) above the mean.

​(Round to two decimal places as​ needed.)

13. If your score on your next statistics test is converted to a z​ score, which of these z scores would you​ prefer:

minus−​2.00,

minus−​1.00,

​0, 1.00,​ 2.00? Why?

A.

The z score of 2.00 is most preferable because it is 2.00 standard deviations above the mean and would correspond to the highest of the five different possible test scores.

B.

The z score of

minus−2.00

is most preferable because it is 2.00 standard deviations below the mean and would correspond to the highest of the five different possible test scores.

C.

The z score of 1.00 is most preferable because it is 1.00 standard deviation above the mean and would correspond to an above average test score.

D.

The z score of

minus−1.00

is most preferable because it is 1.00 standard deviation below the mean and would correspond to an above average test score.

E.

The z score of 0 is most preferable because it corresponds to a test score equal to the mean.

Answer 1

8.

variance of their​ weights = standard deviation² = 12.4989² = 156.2225 .kg2.

9.

The data is,

97 40 66 3 52 50 91 73 84 85 2

The data in ascending order is,

2 3 40 50 52 66 73 84 85 91 97

Range = Maximum - Minimum = 97 - 2 = 95

Mean = (97 + 40 + 66 + 3 + 52 + 50 + 91 + 73 + 84 + 85 +2) / 11 = 58.45455

Sample standard Deviation = sqrt[((97 - 58.45455)² +  (40 - 58.45455)² +  (66 - 58.45455)² +  (3 - 58.45455)² +  (52 - 58.45455)² +  (50 - 58.45455)² +  (91 - 58.45455)² +  (73 - 58.45455)² +  (84 - 58.45455)² +  (85 - 58.45455)² +  (2 - 58.45455)² ) / (11 - 1)]

= 32.99504 33.0

Variance = 32.99504² = 1088.7

12.

The​ player's height is 1.95 standard​ deviation(s) above the mean

13.

We will prefer the highest Z score. So, the answer is

A.

The z score of 2.00 is most preferable because it is 2.00 standard deviations above the mean and would correspond to the highest of the five different possible test scores.