Question

On August 25, 1894, Chicago catcher William Schriver caught a baseball thrown from the top of the Washington Monument (555 ft, 898 steps).

Part A.) If the ball was thrown horizontally with a speed of 7.50 m/s , where did it land?

Part B.) What was the ball's speed of motion when caught?

Part C.) What was the ball's direction of motion when caught?

Answer 1

Given initial launch height,

Initial vertical launch velocity,

Initial horizontal launch velocity,

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Time of flight

Consider vertical motion of the ball

Use formula

Part A.) If the ball was thrown horizontally with a speed of 7.50 m/s , where did it land?

Consider horizontal motion of the ball

There is no acceleration in horizontal direction, so horizontal velocity remains same.

Horizontal velocity = Distance/Time

ANSWER :

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Part B.) What was the ball's speed of motion when caught?

There is no acceleration in horizontal direction, so horizontal velocity remains same.

Consider vertical motion of the ball

Use formula

downwards

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Velocity,

ANSWER :

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Part C.) What was the ball's direction of motion when caught?

Direction

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