Question

In: Statistics and Probability

Researchers were curious on how accurate people are at judging distances in different body orientations. Participants...

Researchers were curious on how accurate people are at judging distances in different body orientations. Participants viewed a target shown in front of them while "standing" (upright), "supine" (lying down on their back), or "prone" (lying on their stomach). They had to judge how far away the target was from them (in centimetres), then the researchers recorded the errorsthey made.

Using the data below, conduct a repeated measure ANOVA to determine whether different body orientations make any difference in people's judgment of distance. Use α = .05. Report η², and if the ANOVA is significant conduct a post-hoc test using Tukey’s HSD. Finally, please state all the steps and the formulas you used and report your conclusion clearly in words.

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Subject          Standing          Supine          Prone

1                        -1                     -4                 -2

2                        -3                     -2                 -3

3                         2                       2                 -1

4                         0                     -2                 -3

5                         2                     -1                   0

6                        -3                     -5                 -4

7                         4                       1                  0

8                        -2                     -3                 -2

9                         0                     -1                 -3

10                      -1                     -4                 -3

∑X2                    48                     81                61

SS                     47.6                  44.9             16.9

Solutions

Expert Solution

column data , i (Factor B) standing supine prone
count, ni = 10 10 10
mean , x̅ i =Σxi / ni -0.200 -1.900 -2.100
std. dev., si = 2.30 2.23 1.37
sample variances, si^2 = 5.289 4.989 1.878
SS ,Σ(x-Xbar)² 47.6 44.9 16.9
grand mean , x̅̅ = ΣXij/Σn =  
square of deviation of sample mean from grand mean,( x̅ - x̅̅)² 1.4400 0.2500 0.4900
SS(between)= SSB = Σni( x̅ i - x̅̅)² = 14.4000 2.5000 4.9000
Factor A
count, n j mean , x̅ j =Σxj/nj std. dev., sj sample variances, sj^2 ( x̅ j - x̅̅)² nj( x̅j - x̅̅)²
3 -2.33 1.5275 2.333 0.871 2.613
3 -2.67 0.5774 0.333 1.604 4.813
3 1.00 1.7321 3.000 5.760 17.280
3 -1.67 1.5275 2.333 0.071 0.213
3 0.3 1.5275 2.333 3.004 9.013
3 -4.0 1.0000 1.000 6.760 20.280
3 1.6666667 2.0817 4.333 9.404 28.213
3 -2.333333 0.5774 0.333 0.871 2.613
3 -1.333333 1.5275 2.333 0.004 0.013
3 -2.666667 1.5275 2.333 1.604 4.813
SSA = total= 89.867
SSA=Σnj( x̅j - x̅̅)² = 89.867
SST = Σ(Xij - X̅̅ ) = 131.2
SSE = SST-SSA-SSB = 19.533
ΣXi² = 190
SST=Σxi² - (Σxi)²/N= 131.2
so, SSA= 89.867
SSB= 21.8
SSE= 19.533
df factor A(row) = r-1 = 9
df factor B(column) = c-1 = 2
here,total observations, N = 30
df error = (r-1)(c-1) = 18
mean square factor A , MSA = SSA/df= 9.99
mean square(factor B) =MSB= SSB/df = 10.90
mean square error = MSE =SSE/df = 1.09
ANOVA
Source of Variation SS df MS F-stat p-value F-critical Result
Rows 89.8667 9 9.9852 9.201 0.0000 2.46 significant
Columns 21.8000 2 10.9000 10.044 0.0012 3.555 significant
Error 19.5333 18 1.0852
Total 131.2000 29
α = 0.05

/.......................

tukey test:

Level of significance 0.05
no of treatments 3
df error 18
MSE 1.0852
q-statistic value 3.6093
confidence interval
population mean difference critical value lower limit upper limit result
µ1-µ2 1.7 1.19 0.51 2.89 means are different
µ1-µ3 1.9 1.19 0.71 3.09 means are different
µ2-µ3 0.2 1.19 -0.99 1.39 means are not different

....................

Please let me know in case of any doubt.

Thanks in advance!


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