Solve the given initial-value problem. y'' + 4y' + 4y = (5 +
x)e^(−2x) y(0) = 3, y'(0) = 6
Arrived at answer
y(x)=3e^{-2x}+12xe^{-2x}+(15/2}x^2e^{-2x}+(5/6)x^3e^{-2x) by using
variation of parameters but it was incorrect.
Solve the initial value problem: y'' + 4y' + 4y = 0; y(0) = 1,
y'(0) = 0.
Solve without the Laplace Transform, first, and then with the
Laplace Transform.